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A straight line passes through two points with co-ordinates (6 8) and (0 5). Work out the equation of the line?
Wiki User
∙ 7y ago
Co-ordinates: (6, 8) and (0, 5)
Slope: 1/2
Equation: 2y = x+10
Wiki User
∙ 7y ago
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What is an equation of the line that passes through the point 14 and has a slope of 3?
"14" is not a point; you need two coordinates to specify a point.
What is the equation of the line that passes through the points (-42) and (4-2)?
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
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It is: y = 8 which will be a straight line parallel to the x axis
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If the function is a straight line equation that passes through the graph once, then that's a function, anything on a graph is a relation!
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It appears that the point has only one coordinate: 310. In two dimensional space, such as the coordinate (or Cartesian) plane, a point needs two coordinates.
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Click on the equation for a line that passes through these coordinates:(1, -2) (2, -6)?
y + 4x = 2
What is an equation of the form ymx for the line that passes through the origin and has slope 2?
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What is an equation of the line that passes through the point 14 and has a slope of 3?
"14" is not a point; you need two coordinates to specify a point.
A straight line passes through point 3comma 5 having no slope the equation of line will be?
y=5
What is the equation of the straight line that passes through the points 0 -4 and 4 8?
y = 3x-4
What is a line that passes through the origin and has a slope of 1 called?
It is a straight line equation in the form of: y = x
Enter an equation of the form y equals mx for the line that passes through the origin and has slope 2?
UndefinedImproved Answer:-The straight line equation is: y = 2x
When a Slope m is 3 passes through point (-2 -1) the graph will?
The straight line equation will then be: y = 3x+5
How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
What is the equation of the line that passes through the points (-42) and (4-2)?
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
What is the equation of the line that has a slope of 0 and passes through the point 6 8?
It is: y = 8 which will be a straight line parallel to the x axis
