The numbers could be from the sequence with a(1) = -3 and the common ratio r = (-2)If so, then
a(7) = -3*(-2)^6 = -3*64 = -192.
Of course, it is entirely possible that the numbers do not form a geometric sequence but a polynomial sequence such as
a(n) = (27*n^3 - 189*n^2 + 396*n - 240)/2 and if so, a(7) = 1266.
You solve ___x 3 by adding the number you are multiplying 3 times!
2x + 3= 9.X=
24/3=8
So the problem is: Solve: 4x2 - x = 3
3^(-4) = (1/3)^4 = 1/81
Yes - 612/3 = 204
612 = 2*2*3*3*17.
If you mean 1/3 of 612 then it is 204
call 612 4082660
Factor Tree of 612: ..........612 ............/ \ ........12 * 51 ......../ \ ......6 * 2 ...../ \ ...2 * 3 Prime factorization of 612 = 2 * 2 * 3 * 51
3 612 in word form is three thousand six hundred twelve.
The GCF of 15 and 612 is: 3
204
1836/3 = 612
5 - 710 - 6r = -93-705 - 6r = -93 705 + 6r = 93 6r = 93 - 705 = -612 r = -612/6 = -102
612 = 2 x 2 x 3 x 3 x 17 = 22 x 32 x 17
yes 1836 is divisible by 3 the answer is 612