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How do you solve this combinations problem. There are 20 students in one class. They need to form groups of at least 2 people and at most 4 people. In how many different ways can they do that?
Wiki User
∙ 12y ago
Combinations of 2: 20*19/(1*2) = 190
Combinations of 3: 20*19*18/(1*2*3) = 1140
Combinations of 4: 20*19*18*17/(1*2*3*4) = 4845
So 6175 in all.
Wiki User
∙ 12y ago
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An algebra class of 21 students must send 5 students to meet with the principal How many different groups of 5 students could be formed from this class?
To find the number of different groups (a) within a larger group (b), use the formula b!/a!.(b-a)! where the ! sign indicates "factorial". In your problem b = 21 and a = 5 so we have 21!/(5!.16!) this simplifies to 21.20.19.18.17/5.4.3.2 cancelling leaves 21.19.3.17 ie 20349
How many ways can a group of 3 students be chosen from a class of 30 students?
3 students can be chosen from a class of 30 in (30 x 29 x 28) = 24,360 ways.But each group of the same 3 students will be chosen in six different ways.The number of different groups of 3 is 24,360/6 = 4,060 .
How many ways can 12 students be split up in groups of 4?
(12 x 11 x 10 x 9)/(4 x 3 x 2 x 1) = 11,880/24 = 495 different groups.Three groups every time.495/3 = 165 ways for the different groups to stand.
If you have 18 plums can you find 6 different ways to show equal groups?
18 groups of 4
How many three member teams can be formed from a group of six students?
2 groups. 2 x 3= 6
How do you solve this combinations problem .There are 20 students in one class. They need to form groups of at least 2 people and at most 4 people. In how many different ways can they do that?
There are only two possibilities... 10 groups of 2 or 5 groups of 4. Unless - you can have varying sized groups - which you didn't specify.
How do you solve this math problem In an Informatics course there are 40 students The professor defined 6 different projects and told the students to form groups of maximum 8 students?
No problem has been defined.
How many different groups of 8 students can you create from a class of thirty students?
30C8 = 5,852,925
How combination in a 9 digit number?
There are different numbers of combinations for groups of different sizes out of 9: 1 combination of 9 digits 9 combinations of 1 digit and of 8 digits 36 combinations of 2 digits and of 7 digits 84 combinations of 3 digits and of 6 digits 126 combinations of 4 digits and of 5 digits 255 combinations in all.
How many different groups of 5 students can be chosen from 23 students?
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
How many different groups of 3 students can be formed if there are 20 students in the class?
20 x 19 x 18/3 x 2 = 1,140 groups
How many 3 letter combinations are in ahtm?
There are four different groups of three, each of which can be arranged in six different ways so your answer is 24.
An algebra class of 21 students must send 5 students to meet with the principal How many different groups of 5 students could be formed from this class?
To find the number of different groups (a) within a larger group (b), use the formula b!/a!.(b-a)! where the ! sign indicates "factorial". In your problem b = 21 and a = 5 so we have 21!/(5!.16!) this simplifies to 21.20.19.18.17/5.4.3.2 cancelling leaves 21.19.3.17 ie 20349
Should 10th board exam be scrapped?
ya board exam is necessary...Because it ll mainly affect the diploma students....it ll create a problem in choosing different types of groups...
Four people from a group of 300000 radio listeners are eligible for a free vacation How many different groups of vacationers are possible?
combinations
What is formulation policy?
Many different groups will come up with plans to fix the problem
What policy formulation?
Many different groups will come up with plans to fix the problem
