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log 25.65

First of all there are two 'logarithm' functions on a calculator. They are shown by 'log', and 'ln'.

'Log' is the function of logarithms to base '10'.

'ln' is is the function of logarithms to the 'natural base' , which is 'e = 2.7818...;.

However, in your question you quote 'log' , so it is assumed you are working to base '10'.

On my calculator press ' clear' , then 'log' the enter '25.65' , then 'equals(-)'. The answer is '1.409087369.... '

NB My calculator is a 'Casio fx-83MS' ; a rather 'ancient machine'.

Different calculator manufacturers will have a different function rountine. Read the instruction paper with your calculator.

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lenpollock

Lvl 16
5mo ago

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Use your calculator to evaluate e-1 Round your answer to four decimal places and enter it below?

0.3679


How do you input log base 3 in a calculator?

Let y = log3 x⇒ x = 3yTaking logs to any base you like of both sides gives:log x = y log 3⇒ y = log x/log 3So to calculate log base 3 on a calculator, use either the [log] (common or log to base 10) or [ln] (natural or to base e) function key for the log above, that is use one of:[(] [log] [] [÷] [log] [3] [)][(] [ln] [] [÷] [ln] [3] [)][(] [] [log] [÷] [3] [log] [)][(] [] [ln] [÷] [3] [ln] [)]Things in square brackets [] represent keys on the calculator; the is the number of which you want the logarithm to base 3.Use one of 1 & 1 if your calculator is a more modern one that uses natural representation that looks like maths whereby the calculation is done once you've finished entering it all and the numbers for functions follow them.Use one of 3 & 4 if your calculator is an older style one that when you press a function key it acts immediately on the number displayed on the screen.The parentheses (round brackets) are included above so that the whole expression evaluates to log3.


How do you solve 4 to the power of x equals 128?

If we take the logarithm of both sides, then it is log(4^x) = log(128). Then from logarithm rules, this can be changed to: x*log(4) = log(128), then x = log(128)/log(4). You can punch this into a calculator and get the answer, but what if we use log base 2, we don't need a calculator. So log2(4) = 2, because 2² = 4. And log2(128) = 7, because 2^7 = 128. So we have x = 7/2 = 3.5, then you can check your answer: 4^3.5 = (4^3)*(4^.5). So 4 cubed = 64, and 4 raised to the 1/2 power is the square root of 4, which is 2. So 64 times 2 = 128.


What is x if 2 to the x power equals 0.5?

2x = 0.5: This is like asking for the logarithm of 0.5, to the base 2. A scientific calculator normally has logarithms for base 10 and base e, but not for other bases. However, you can calculate this is log(0.5) / log(2). It doesn't matter what base you use for your logarithms, just keep it consistent. For example, with base 10, log(0.5) / log(2) = -0.301 / 0.301 = -1.


What is log 50 to the base 0.1?

log0.1 50 = log10 50 / log10 0.1 ~= -1.699 To work out the log to any base b, logs to another base can be used: When logs are taken of a number to a power, then the power is multiplied by the log of the number, that is: log(bn) = n log b Taking logs to base b the power of b that equals the original number is being found, that is if: bn = m then logb m = n So, by using the logs to a base to which the answer can be known, the log to any base can be calculated: bn = m => n log b = log m => n = log m / log b => logb m = log m / log b as long as the same base is used for the logs on the right. It is normal to use base 10 or base e which are found on calculator buttons marked log (base 10) and ln (log natural - base e).

Related Questions

Log (xy) where x12 and y20?

To simplify (\log(xy)), you can use the logarithmic property that states (\log(xy) = \log(x) + \log(y)). Given (x = 12) and (y = 20), you can calculate (\log(12) + \log(20)). If you need a numerical value, you can evaluate it using a calculator, resulting in approximately (1.0792 + 1.3010 = 2.3802) (using base 10 logarithm).


What is log base 4 of 27?

You can calculate that on any scientific calculator - like the calculator on Windows (if you change the options, to display as a scientific calculator). Log base 4 of 27 is the same as log 27 / log 4. You can use logarithms in any base to calculate that - just use the same base for both logarithms.


What is the log of 14?

You should use a calculator for a question like this. It is quicker and simpler. Log(14) = 1.15


How do you find logarithms using a calculator?

If you are using a scientific calculator you will have a key labelled "log". To find the logarithm (to base 10) of a number, simply enter "log" followed by the number that you want to log. If you want a natural logarithm - log to the base e - use the "ln" key instead. If you haven't got a scientific calculator, use the one on your computer.


How do you find log values?

You look them up in log tables, or use a scientific calculator. The calculators use a method based on the Taylor series.


How do you evaluate 4602 divided by 37?

124.3784


How do you use the anti log on a TI-89 calculator'?

To find anti log of a number enter the number as the exponent of 10.


How do you calculate an antilog on a TI-86 calculator?

The anti-log is "10^x" listed above the "LOG" key on a TI-86 calculator. All you have to do to use it is press the yellow "2nd" key (this means shift) and then press the "LOG" key.


How do you find log of no?

Look it up in table of logarithms or use "log" button on scientific or other calculator. You might even be able to Google it!


Use your calculator to evaluate e-1 Round your answer to four decimal places and enter it below?

0.3679


How do you use inverse log on graphing calculator?

The inverse of a logarithmic function is an exponential function. So to find the "inverse" of the log function, you use the universal power key, unless you're finding the inverse of a natural log, then you use the e^x key.


How do you get 1048576 to the fifth power?

You can do it directly on a calculator and get 1.2676506002282e+30. Or you can use logs like y=n^5 and log y=5*log(1048576)=30.102999566398. Look up the anti-log for the answer.