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If Keoki has 14 quarters and 8 dimes (for a total of 22 coins), she has $3.50 and $0.80 or $4.30 in coins. If Keoki has 15 quarters and 7 dimes (for a total of 22 coins), she has $3.75 and $0.70 or $4.45 in coins. If Keoki has 22 coins that are all dimes and quarters and their value in total is $4.35 as asked, there isn't a combination of coins that will permit her to have both 22 coins and $4.35 worth of coins.

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Q: Keoki has 22 coins that are all dimes and quarters. If their value is 4.35 how many dimes and quarters does Keoki have?
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What are 5 coins that have a total value of 1.05?

4 quarters and one nickel


A vending machine takes only nickels and dimes. There are 5 times many dimes as nickels in the machine. The face value of the coins is 4.40. How many of each coin are in the machine?

40 Dimes and 8 Nickles


If a collection of dimes is arranged in a triangular array with 14 coins in the base row13 in the next 12 in the next and so forth. Find the value of the collection.?

If there are 14 rows in the triangle, then there are 14*(14-1)/2 coins in the arrangement, i.e. 91 dimes. To find the value of the collection, simply multiply by the value of a dime. I believe this is 10 cents, so the coins are worth 910 cents, or $9.10.


If you have 2.35 in dimes and nickels and you have one more dime than nickels how many of each do you have?

Set up your equations based upon the following: Let N = number of nickles. Let N + 1 = number of dimes. Let 5N = the value (in cents) of all the nickles. Let 10(N + 1) = the value (in cents) of all the dimes. Let 235 = the total value (in cents) of all the coins (nickles and dimes). In English, the value of the dimes plus the value of the nickles equals the total value of the coins. Algebraically, we write: 5N + 10(N + 1) = 235 The distributive law of multiplication lets us rewrite that this way: 5N + 10N + 10 = 235 Grouping lets us write that this way: 15N + 10 = 235 Subtracting 10 from both sides of the equation yields: 15N = 225 Dividing both sides by 15 yields: N = 15 So, we have 15 nickles and 15 + 1, or 16, dimes.


How many coins of each type does Cameron have if he has 4.50 in nickels and dimes in his piggy bank and the number of dimes is twice the number of nickels?

In order to eliminate the decimal point, let us work with cents. So, let $ 4.50 = 450 cents. If the number of nickels is x, then the value of x nickels is 5x cents. Since the number of dimes is twice the number of nickels, then we can write the number of dimes as 2x, and the value of 2x dimes as 10(2x) or 20x cents. So we have: 5x + 20x = 450 25x = 450 divide by 25 to both sides x = 18 the number of nickels 2x = 2 x 18 2x = 36 the number of dimes Thus, Cameron has 18 nickels and 36 dimes. Check: 18 nickels = 18 x 5 cents = 90 cents or $ 0.90 36 dimes = 36 x 10 cents = 360 cents or $ 3.60 0.90 + 3.60 = 4.50? 4.50 = 4.50 True

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