If Keoki has 14 quarters and 8 dimes (for a total of 22 coins), she has $3.50 and $0.80 or $4.30 in coins. If Keoki has 15 quarters and 7 dimes (for a total of 22 coins), she has $3.75 and $0.70 or $4.45 in coins. If Keoki has 22 coins that are all dimes and quarters and their value in total is $4.35 as asked, there isn't a combination of coins that will permit her to have both 22 coins and $4.35 worth of coins.
4 quarters and one nickel
40 Dimes and 8 Nickles
If there are 14 rows in the triangle, then there are 14*(14-1)/2 coins in the arrangement, i.e. 91 dimes. To find the value of the collection, simply multiply by the value of a dime. I believe this is 10 cents, so the coins are worth 910 cents, or $9.10.
Set up your equations based upon the following: Let N = number of nickles. Let N + 1 = number of dimes. Let 5N = the value (in cents) of all the nickles. Let 10(N + 1) = the value (in cents) of all the dimes. Let 235 = the total value (in cents) of all the coins (nickles and dimes). In English, the value of the dimes plus the value of the nickles equals the total value of the coins. Algebraically, we write: 5N + 10(N + 1) = 235 The distributive law of multiplication lets us rewrite that this way: 5N + 10N + 10 = 235 Grouping lets us write that this way: 15N + 10 = 235 Subtracting 10 from both sides of the equation yields: 15N = 225 Dividing both sides by 15 yields: N = 15 So, we have 15 nickles and 15 + 1, or 16, dimes.
In order to eliminate the decimal point, let us work with cents. So, let $ 4.50 = 450 cents. If the number of nickels is x, then the value of x nickels is 5x cents. Since the number of dimes is twice the number of nickels, then we can write the number of dimes as 2x, and the value of 2x dimes as 10(2x) or 20x cents. So we have: 5x + 20x = 450 25x = 450 divide by 25 to both sides x = 18 the number of nickels 2x = 2 x 18 2x = 36 the number of dimes Thus, Cameron has 18 nickels and 36 dimes. Check: 18 nickels = 18 x 5 cents = 90 cents or $ 0.90 36 dimes = 36 x 10 cents = 360 cents or $ 3.60 0.90 + 3.60 = 4.50? 4.50 = 4.50 True
Mula has 16 dimes and 11 quarters.
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
One roll of dimes contains 50 coins for a value of $5. Quarters come in rolls of 40 for a value of $10.
30 quarters equals $7.50 42 dimes equals $4.20 That adds up to 72 coins with a value of $11.70
8 quarters, 5 dimes
8 of them.
All coins such as quarters, nickels, dimes, and half dollars
Not possible, the maximum value of 1 dime and 56 quarters is $14.10. Increasing the number of dimes reduces the total value by 15c per dime
If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.
The denominations for 1959 were: Half dollars, Quarters, Dimes, Nickels and Cents.
2 quarters 5 dimes 10 nickels 50 pennies
8 rolls of pennie’s 6rolls of nickels 3 rolls of dimes 9rolls of quarters