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Q: We are interested in the dimensions of a certain rectangle. This rectangle has length twice the side of the square and width three units less than its sides of this square. If the two areas are equal?
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How do you calculate the dimensions of a rectangle if you know the perimeter and the length?

A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.


The length of a rectangle is 4 cm more than the width If the perimeter of the rectangle is 20 cm what are the dimensions?

length + width = 20/2 = 10 length = 7cm, width = 3cm


We are interested in the dimensions of a certain square. A rectangule has length twice the side of this square and width three less than theside If two areas are equal what are the square's dimension?

Area of square = x2Area of rectangle = 2x * (x-3)The two area are the same so x2 = 2x2 - 6xso x2 = 6xso x = 6The square has sides of length 6A+ = x2 = 2x2 - 6


How do you find height when length and breadth are given in rectangle?

A rectangle is a 2-dimensional object. It cannot have length and breadth AND height. If three dimensions are given, then two of them (eg breadth and height) must stand for the same thing.


You are interested in the dimensions of a certain square A rectangle has length 5 units more than the side of this square and width half the side of this square Which equation describes this situatio?

The quadratic equation of the square is probably x2-5x+6.25 = 0 because its discriminant is equal to zero giving the equation equal roots of x = 5/2 and x = 5/2