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Q: What is 4x times 2.5?

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I believe you are asking: What is the derivative (d/dx) of (4x+25)^0.5 If this is indeed the case, the derivative d((4x+25)^0.5)/dx = 0.5*(4x+25)^-0.5*4 = 2(4x+25)^-0.5 That is, 2 times the quantity (4x+25) to the negative 1/2 power.

When -25=4x+7 Then -25-7 = 4x And -32 = 4x So the number is -32/4 = -8

16x2 - 25 = (4x + 5) ( 4x - 5)

Use the FOIL method. (4x^3 - 4)(x^2-25) 4x^3*x^2=4x^5 -4*x^2=-4x^2 4x^3*-25=-100x^3 -4*-25=100 4x^5-100x^3-4x^2+100 Factor out a 4 to simplify 4(x^5-25x^3-x^2+25)

16x2 - 25 = (4x + 5) (4x - 5)

4x+9=25 4x+9=25-9 4x/4=1 16/4=4 4x+9=26 4(4)+9=25 16+9=25 The answer is 4

16x2 + 40x + 25 = 16x2 + 20x + 20x + 25 = 4x(4x + 5) + 5(4x + 5) = (4x + 5)(4x + 5) = (4x + 5)2

4x × 4x = (4x)² = 16x²

4x+9=25 4x=16 x=4

10x - 25 = 4x + 510x - 4x = 25 + 56x = 30x = 5

4x

4x * x = 4x^2

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