120 inches (by finding the hypotenuse of a right triangle).
38.42 feet.
43.26661530556787
Lets work it out:- If the legs are 12 and 16 inches, then a rectangle of that size would be 192 square inches in area. As the the diagonal of the rectangle makes two equal triangles (of legs 12 and 16 inches), the area of one of these is half the area of the triangle - 192/2 = 96 square inches.
302+482=3204 squareroot(3204) Answer=56.60388679
15 cm Solved through Pythagoras' theorem.
26.4 inches for the diagonal.
The diagonal is 221.2 inches long.
157.6102789 inches
44 feet 4 inches
Using Pythagoras' theorem it is 26 inches in length
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
15 inches (solved with the help of Pythagoras' theorem)
The diagonal is 15.652'
The diagonal is 14.21 cm
The diagonal would be 12.53 meters.
The diagonal is 100'
The diagonal is 47.707'