2)48
2)24
2)12
2)6
3)3 =1
So factors are 2x2x2x2x3 = 2^(4) x 3^(1)
The prime factorization of 48 is 2*2*2*2*3
The Highest Common Factor (HCF) of 16, 48, and 60 is 4. To find the HCF, you need to factorize each number into its prime factors. The prime factors of 16 are 2^4, the prime factors of 48 are 2^4 * 3, and the prime factors of 60 are 2^2 * 3 * 5. The HCF is the product of the common prime factors raised to the lowest power, which in this case is 2^2 = 4.
The largest perfect square factor of 48 is 16.
Find the prime factors of 48 and 108: 48 = 2*2*2*2*3 108 = 2*2*3*3*3 Now multiply the common factors: GCF = 2*2*3 = 12
12, 24, and 48 are all multiples of 12 and factors of 48.
48 24,2 12,2,2 6,2,2,2 3,2,2,2,2
48 24,2 12,2,2 6,2,2,2 3,2,2,2,2
Use a factor tree. 48 24,2 12,2,2 6,2,2,2 3,2,2,2,2
23
48 = 2⁴×3
48 24,2 12,2,2 6,2,2,2 3,2,2,2,2
48 24,2 12,2,2 6,2,2,2 3,2,2,2,2
Divide prime numbers into it. Start with 2. Do that four times. Then try 3. Stop.
48 24,2 12,2,2 6,2,2,2 3,2,2,2,2
546 273,2 91,3,2 13,7,3,2
To find the prime factorization of 48 using a factor tree, we start by breaking down 48 into its factors, such as 2 and 24. Then, we continue breaking down 24 into 2 and 12, and 12 into 2 and 6. Finally, we break down 6 into 2 and 3. This gives us the prime factorization of 48 as 2^4 * 3.
24 is a factor of 48. But, 24 is not a prime factor because it is a composite number.