Rounded to five decimal places, sqrt(89) = ±9.43398
The square root of 89 (written √89 or 891/2) = 9.434 (3dp)
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Such that the square root of 89, rounded to five decimal places, is equal to 9.43398, the square root of -89 is equal to 9.43398 i, the lower-case i representing the square root of minus 1.
The square root of 7921 is 89.
It is: 9.434 rounded
sqrt(89) = -9.4 or +9.4 So one possible pair of consecutive integers between the square roots of 89 are 2 and 3.
The numbers are 88 and 89 (88 x 89 = 7,832). This is very easy to find. The products you are looking for are consecutive and so they are very close to each other. Calculate the square root of the number, and it is easy to see that if there are two consecutive whole numbers that will be products of the number, they will be consecutive whole numbers very close to the square root. The square root of 7832 is about 88.5.
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