7
15 = 31*51
write the number 14as a product of prime factor?
It is: 2^1 times 3^2 times 5^2 = 450
As a product of its prime factors: 5*5*5*11 = 1375
As a product of its prime factors: 2*5*5*5 = 250
As a product of its prime factors: 23*3*5 = 120
48 = 24 x 3
15 = 31*51
As a product of its prime factors: 3*7 = 21
write the number 14as a product of prime factor?
It is: 2^1 times 3^2 times 5^2 = 450
As a product of its prime factors: 3*5*7*7 = 735
As a product of its prime factors: 5*5*5*11 = 1375
As a product of its prime factors: 2*5*5*5 = 250
As a product of its prime factors: 3*5*7*11 = 1155
write the prime factorization of the number. simple as that.
To express 144 as a product of its prime factors in index form, we first find the prime factors of 144, which are 2 and 3. 144 can be written as 2^4 * 3^2 in index form, where 2 is raised to the power of 4 and 3 is raised to the power of 2. This shows that 144 can be expressed as the product of its prime factors in index form.