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The factor pairs of 125 are 1 x 125 and 5 x 25
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∙ 7y ago
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What are the factors of 125 in pairs?
125 = 1 x 125125 = 5 x 25
What are the factors 125?
The factors of 125 are: 1, 5, 25, 125
What are all the factors for 125?
The factors of 125 are: 1, 5, 25, 125.
Factors are 5 and 125 what is the product?
5 and 125 are factors of 125. The product of 5 and 125 is 625.
What are all of the factor pairs of 125?
There are two: 125 = 1 x 125 125 = 5 x 25
What two numbers multiplied equal 125?
There are an infinite number of pairs. If you restrict yourself to integers there are only two pairs: (1, 125), and (5,25). Otherwise, (1/2, 125*2), (1/3, 125*3) etc gives one form of such pairs.
What are the factors and prime factors of 125?
The 4 factors of 125 are 1, 5, 25, and 125.The factor pairs of 125 are 1 x 125 and 5 x 25.The proper factors of 125 are 1, 5, and 25 or,if the definition you are using excludes 1, they are 5 and 25.The prime factors of 125 are 5, 5, and 5.Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The only distinct prime factor (listing each prime factor only once) of 125 is 5.The prime factorization of 125 is 5 x 5 x 5 or, in index form (in other words, using exponents), 53.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple of a single number because "common" refers to factors or multiples that two or more numbers have in common.1, 5, 25, 125
What are the factors of negative 125?
The factors of -125 are 1, 5, 25, 125, -1, -5, -25, and -125.
Factors and prime factors of 125?
1, 5, 25, 125 are the factors of 125. 5 is the only prime factor.
What are the two factors of 125?
125 actually has four factors: 1, 5, 25 and 125.
What are the common factors of 125?
The factors of 125 are 1, 5, 25, 125. For them to be common, they need to be compared to another set of factors.
If pairs of factors separate independently of other pair factors you are dealing with?
If pairs of factors separate independently of other pairs of factors, you are dealing with the: Law of independent assortment
