540 x 2
Prime factors of 1080 are 23 33 5.
Prime factors in exponent form: 2^3 * 3^3 * 5
There is more than one possible answer. The prime factors of 16 are 2, 2, 2, and 2. It has four prime factors, but only one distinct prime factor. The prime factors of 24 are 2, 2, 2, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 36 are 2, 2, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 40 are 2, 2, 2, and 5. It has four prime factors, but only two distinct prime factors. The prime factors of 54 are 2, 3, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 56 are 2, 2, 2, and 7. It has four prime factors, but only two distinct prime factors. The prime factors of 60 are 2, 2, 3, and 5. It has four prime factors, but only three distinct prime factors. The prime factors of 81 are 3, 3, 3, and 3. It has four prime factors, but only one distinct prime factor. The prime factors of 84 are 2, 2, 3, and 7. It has four prime factors, but only three distinct prime factors. The prime factors of 88 are 2, 2, 2, and 11. It has four prime factors, but only two distinct prime factors. The prime factors of 90 are 2, 3, 3, and 5. It has four prime factors, but only three distinct prime factors.
1080 = 2 x 2 x 2 x 3 x 3 x 3 x 5
The prime factors of 336 are: 2,3,7
Prime factors of 1080 are 23 33 5.
Prime factors in exponent form: 2^3 * 3^3 * 5
The Highest Common Factor (HCF) of 480 and 1080 is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF, we need to factorize both numbers into their prime factors. The prime factors of 480 are 2^5 x 3 x 5, and the prime factors of 1080 are 2^3 x 3^3 x 5. To find the HCF, we take the common prime factors with the lowest exponent, which are 2^3 x 3 = 24. Therefore, the HCF of 480 and 1080 is 24.
Any of its factors will divide into 1080 evenly
23 x 33 x 5 = 1080
23 x 33 x 5 = 1080
Prime factors are factors that are also prime numbers.
The common factors are: 1, 2, 3, 6.
The prime factorization of 1,080 using exponents is: 23x 33 x 5
There is more than one possible answer. The prime factors of 16 are 2, 2, 2, and 2. It has four prime factors, but only one distinct prime factor. The prime factors of 24 are 2, 2, 2, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 36 are 2, 2, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 40 are 2, 2, 2, and 5. It has four prime factors, but only two distinct prime factors. The prime factors of 54 are 2, 3, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 56 are 2, 2, 2, and 7. It has four prime factors, but only two distinct prime factors. The prime factors of 60 are 2, 2, 3, and 5. It has four prime factors, but only three distinct prime factors. The prime factors of 81 are 3, 3, 3, and 3. It has four prime factors, but only one distinct prime factor. The prime factors of 84 are 2, 2, 3, and 7. It has four prime factors, but only three distinct prime factors. The prime factors of 88 are 2, 2, 2, and 11. It has four prime factors, but only two distinct prime factors. The prime factors of 90 are 2, 3, 3, and 5. It has four prime factors, but only three distinct prime factors.
1080 = 2 x 2 x 2 x 3 x 3 x 3 x 5
The prime factors of 336 are: 2,3,7