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What are the factors of this quadratic trinomial 12x2 plus 13x 35?
Wiki User
∙ 12y ago
12x2+13x-35 = (4x-5)(3x+7)
12x2 + 13x- 35 let's find two factors of -420 (12*-35) whose sum is 13, which are 28 and -15
(12x + 28)(12x - 15) now simplify by 4 and 3
(3x + 7)(4x - 5)
Wiki User
∙ 13y ago
Wiki User
∙ 12y agoFactors of 12 and 35 which can equal 13 are 3/4 and 5/7 so:
(3x - 7)(4x + 5) assuming the sign of 35 in your equation is "-".
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