2.4 x 8.6
The number of decimal places for the product will be the summation of the amount of decimal places of the 2 factors. For example, if your products have 2 decimals each to the right of zero then the product will have an answer with 4 decimals to the right of zero.
* One decimal place. * To the tenth place.
Not necessarily: for example, consider 0.5 * 4 = 2
As many as required for the accuracy needed
There will be five.
The product of 0.02x 0.02 is 0.0004,and the product of 0.2 x 0.002 is also 0.0004, so they are the same. In each case, the answer requires 4 decimal places. In the first problem, you have two figures with two decimal places each, equaling four decimal places. In the second problem, you have a figure with one decimal place and a figure with three decimal places, also equaling four decimal places.
To find the number of decimal places in a product of decimal numbers, add up the total number of decimal places in each of the factors. For example, if you have 2.5 multiplied by 4.75, there are two decimal places in 2.5 and two decimal places in 4.75, so the product will have a total of four decimal places.
Generally speaking, with the exception of trailing zeroes, the number of decimal places in the answer of a multiplication sum is equal to the sum of the number of decimal places in the question. Therefore, 4.97 x 3.456 contains five decimal places in total, therefore the answer contains five decimal places. In this instance, 4.97 x 3.456 = 17.17632.
the product will have four decimal places
There will be five decimal places.
Since both multiplicands are integers, then so is their product.
Multiply the numbers, count the total number of decimal places in the problem and place that many in your product.
2
three
The number of decimal places for the product will be the summation of the amount of decimal places of the 2 factors. For example, if your products have 2 decimals each to the right of zero then the product will have an answer with 4 decimals to the right of zero.
Six - to the millionths.
At most 3.