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If y varies inversely as the square of x and y equals 4 when x equals 3 find y when x is 2?

Anonymous

∙ 15y ago

Updated: 3/9/2025

y varies as 1/x^(2)

y = k X 1/^(2)

y = k/x^(2)

k = y x^(2)

When y = 4 & x = 3

Then

k = 4(3^(2))

k = 4(9)

k = 36 (The constant of proportionality

Hence the general equation is

y = 36/x^(2)

When x = 2

y = 36/2^(2)

y = 36 /4

y = 9 The answer!!!!!

lenpollock ∙

Lvl 16

∙ 2mo ago

What else can I help you with?

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