Simultaneous Equations
4a - 5b = 7
4a + 5b = 17
Add the two , this will eliminate 'b'
8a = 24
Divide both sides by '8'
a = 3
When a= 3 , substitute into eityher equation for 'b'.
4(3) + 5b = 17
12 + 5b = 17
5b = 17 - 12 = 5
5b = Divide both sides by '5'.
Hence 'b = 1'.
The order pair for the given equations is (4a, 5b). The first element in the pair, 4a, represents the coefficient of the variable a in the equations. The second element in the pair, 5b, represents the coefficient of the variable b in the equations.
You can use the given equations to solve for the values of a and b. For example, to solve for a, you can subtract the second equation from the first equation to get:
4a - 5b - (4a + 5b) = 7 - 17
This simplifies to:
-10b = -10
Therefore, b = 1.
To find the value of a, you can substitute this value back into one of the original equations. For example, substituting b = 1 into the second equation gives:
4a + 5(1) = 17
This simplifies to:
4a + 5 = 17
Therefore, a = 3.
So the solution to the given system of equations is (a,b) = (3,1).
It looks like you have two equations:
4a - 5b = 7
4a + 5b = 17
To find the order pair (a,b) that satisfies both of these equations, you can use the technique of substitution. First, solve one of the equations for one of the variables, such as solving the first equation for a:
a = (7 + 5b)/4
Then substitute this expression for a in the second equation:
4((7 + 5b)/4) + 5b = 17
This simplifies to:
7 + 5b + 5b = 17
Which simplifies to:
12b = 10
Dividing both sides by 12 gives:
b = 10/12
b = 5/6
Substituting this value for b back into the first equation gives:
a = (7 + 5(5/6))/4
a = (7 + 25/6)/4
a = (7 + 25/6)/4
a = (49/6)/4
a = 8/6
a = 4/3
So the order pair that satisfies both equations is (4/3, 5/6).
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Multiply each equation by the value that makes the coefficients of
a
opposite.
(
−
1
)
⋅
(
4
a
−
5
b
)
=
(
−
1
)
(
7
)
4
a
5
b
=
17
Simplify.
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−
4
a
5
b
=
−
7
4
a
5
b
=
17
Add the two equations together to eliminate
a
from the system.
−
4
a
5
b
=
−
7
4
a
5
b
=
1
7
1
0
b
=
1
0
Divide each term in
10
b
=
10
by
10
and simplify.
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b
=
1
Substitute the value found for
b
into one of the original equations, then solve for
a
.
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a
=
3
This is the final solution to the independent system of equations.
b
=
1
a
=
3
add two equations
8a=24
a=3
substitute a=3 in second equation
5b=17-4(3)
5b=5
b=1
solution (3,1)
(1) 4a-5b=7
(2) 4a+5b=17
(1)-(2) gives 4a-5b-(4a+5b)=7-17 then -10b=-10 so b=1
from (2) one gets 4a=17-5b=17-5x1=12 so a=3
(3,1) is the solution
3m+2=17 First, subtract 2 to get m on one side. 3m+2-2=17-2 3m=15 Divide by 3 to get m by itself. 3m/3=15/3 m=5 m equals 5.
17
-3x-8+4x=17(-3x+4x)-8=17 ;combine like terms(x)-8=17 ;add 8 to both sidesx=25
i got x = 1.35 12x+18=41-5x +5x 17x+18=41 -18 17x=23 /17 x=1.35
The value of x is the solution of 4 3x plus 5 17 is given as follows . 12 x + 5 =17. 12x =12. Hence , x=1. ThusThe value of x is the solution of 4 3x plus 5 17 is 1.
(0,7)
119
-2
-17 + y,,must be equals to..-17y..
In roman numerals, XII equals 12, and V equals 5. So as 12 plus 5 equals 17, XII plus V equals 17:) hope it helpedImproved Answer:XII+V = XVII (12+5 = 17)
17 plus 15 plus 13 equals 45.
6
43
Negative 17 plus 121 divided by 8 equals 13.
34 + 17 + 8.5 = 59.5
17 + 25 + 15 = 57
yes it does!