0
Approximally 0.275 moles.
The molar mass of Ca C O3 is ~ 40+12+3*16 = 100g/mol
27.50g = x mol *100g/mol
27.50g/(100g/mol) = x mol
0.275 g/(g/mol) = x mol
0.275 mol = x mol
Wiki User
∙ 11y ago
Wiki User
∙ 13y ago0,2748 mol
equation used: n=m/M
n is amount of substance (in mole)
m is mass of CaCO3 (27.50 g)
M is molar mass (for CaCO3 100,086 g/mol)
Wiki User
∙ 7y agoThe number of moles in 27,50 grams CaCO3 is 0,275.
Wiki User
∙ 14y ago0.275
Wiki User
∙ 13y ago0.2750
Wiki User
∙ 13y ago.2750
Add your answer:
Earn +20 pts
How many moles are there in 250 g of CaCO3?
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
How many moles are in 1.5 grams of iron?
To calculate the number of moles from grams, you must divide by the substance's molar mass
Can you calculate the number of moles of magnesium used grams permol?
Yes
How many liters of carbon dioxide can be obtained from the reaction of 906 grams of calcium carbonate with hydrochloric acid?
To determine the number of liters of carbon dioxide produced in this reaction, we need the balanced equation and the molar mass of carbon dioxide. The balanced equation is: CaCO3 + 2HCl → CaCl2 + CO2 + H2O The molar mass of CO2 is 44.01 g/mol. First, we calculate the number of moles of CaCO3: 906 g / molar mass of CaCO3 = moles of CaCO3 Using the balanced equation, we see that the stoichiometric coefficient of CO2 is 1. This means that the number of moles of CO2 produced is equal to the number of moles of CaCO3. Finally, we convert moles of CO2 to liters using the ideal gas law: moles of CO2 x 22.4 L/mol = liters of CO2. Therefore, the number of liters of CO2 produced from 906 grams of CaCO3 can be calculated as follows: liters of CO2 = (906 g / molar mass of CaCO3) x 22.4 L/mol
Calculate the number of mole of CO2 generated by the reaction of caco3 equals cao plus CO2 when 500 g cao is produce?
The decomposition reaction of calcium carbonate produces calcium oxide and carbon dioxide in a one to one ratio. 500 grams of CaO is 8.92 moles, so 8.92 moles of carbon dioxide are produced.
How many moles are there in 250 g of CaCO3?
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
Calculate the mass in grams of 2.5 moles in calcium carbonate?
For this you need the atomic (molecular) mass of CaCO3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CaCO3= 100.1 grams2.50 moles CaCO3 × (100.1 grams) = 250.25 grams CaCO3
How many moles are in 1.5 grams of iron?
To calculate the number of moles from grams, you must divide by the substance's molar mass
Can you calculate the number of moles of magnesium used grams permol?
Yes
How many liters of carbon dioxide can be obtained from the reaction of 906 grams of calcium carbonate with hydrochloric acid?
To determine the number of liters of carbon dioxide produced in this reaction, we need the balanced equation and the molar mass of carbon dioxide. The balanced equation is: CaCO3 + 2HCl → CaCl2 + CO2 + H2O The molar mass of CO2 is 44.01 g/mol. First, we calculate the number of moles of CaCO3: 906 g / molar mass of CaCO3 = moles of CaCO3 Using the balanced equation, we see that the stoichiometric coefficient of CO2 is 1. This means that the number of moles of CO2 produced is equal to the number of moles of CaCO3. Finally, we convert moles of CO2 to liters using the ideal gas law: moles of CO2 x 22.4 L/mol = liters of CO2. Therefore, the number of liters of CO2 produced from 906 grams of CaCO3 can be calculated as follows: liters of CO2 = (906 g / molar mass of CaCO3) x 22.4 L/mol
Calculate the number of mole of CO2 generated by the reaction of caco3 equals cao plus CO2 when 500 g cao is produce?
The decomposition reaction of calcium carbonate produces calcium oxide and carbon dioxide in a one to one ratio. 500 grams of CaO is 8.92 moles, so 8.92 moles of carbon dioxide are produced.
How do you convert 50 g of calcium carbonate into moles?
1. Calculate formula massCalcium carbonate has chemical formula CaCO3.Its formula mass is 40.1 + 12.0 + 3(16.0) = 100.12. Apply formula to calculate number of moles of CaCO3Amount of CaCO3= mass/formula mass= 50/100.1= 0.50mol
How many grams are in 1.25 moles of calcium carbonate?
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
How many grams of calcium carbonate are needed to produce 93.0 L of carbon dioxide at STP?
At STP one mole of any gas occupies 22.4 L. The equation for the reaction is CaCO3(S) - -> CaO (s) + CO2 (g). Moles of CO2 in 93.0 L is 93/22.4 = 4.15 moles, the ratio of moles of CaCO3 and CO2 is 1:1, therefore 4.15 moles of CaCO3 will be required. 1 mole of CaCO3 is equal to 100.087 g/mol. Therefore, 4 .15 moles will have 415.2 grams.
What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How do you calculate the number of moles in 2.61 grams of silicon?
For this you need the atomic mass of Si. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.2.61 grams Si / (28.1 grams) = .0963 moles Si
How do you calculate the gram molecular weight if you have 3.9176 grams and 0.122400 moles?
See the Related Questions to the left of this answer:"How do you convert from grams to moles and also from moles to grams?"
