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Suppose the plane faces of the cylinder lie in the planes that are s units above and below the centre of the sphere. Therefore, the height of the cylinder is 2*s units.

Also, by Pythagoras's theorem, the radius of the cylinder, x units, is such that

x^2 + s^2 = R^2 = 16

Therefore x^2 = 16 - s^2.

Volume of cylinder = pi*x^2*2*s = 2*pi*(16-s^2)*s = 2*pi*(16*s - s^3)

Then dV/ds = 0 implies that 2*pi*(16 - 3*s^2) = 0 so s^2 = 16/3 and so s = 4/sqrt(3)

The second derivative is -2*pi*6*s which is negative and so the volume is a maximum.

When s = 4/sqrt(3),

Volume of cylinder = 2*pi*[16 - 16/3]*4/sqrt(3) = 2*pi*32/3*4/sqrt(3)

= 256*pi/[3*sqrt(3)]

= 256*sqrt(3)*pi/9 = 49.2672*pi approx.

The volume of the cylinder is approx 0.5774 times that of the sphere.

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9y ago
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13y ago

The volume of the sphere is 268.08 cubic units.

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9y ago

The volume of a sphere with a radius of 24 is about 57,905.8 units3

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9y ago
Volume of the sphere: 4/3*pi*4^3 = 268.083 cubic inches rounded
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Q: What is the volume of a sphere that has a radius of 4 inches?
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What is the volume of a sphere with radius of 4 in?

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