Some of the three characteristics of a wave that can be measured include the frequency, wavelength and amplitude. The amplitude would correspond to loudness in sound waves and brightness where light is concerned.
the 3 charccteristics of s waves are........they are slower than P waves
They are conduted as a shearing motion
They will not travel through liquids or gases because these matrial lack strenght
The equation for a alternating sinusoidal voltage starting from zero volts at time t=0 is V = Vo sin (omega . t)
In general if it crosses zero at a slightly earlier time, it has a phase lead of phi and the equation is:
V = Vo sin (omega.t + phi).
The variables are omega, measured in radians/sec, equal to 2pi times frequency, and the phase-angle phi is measured in radians.
The period T is given by T = 2pi / omega or 1 / frequency.
The root-mean-square value is Vo/sqrt(2).
Frequency, Amplitude, Wave shape and Phase
Frequency, amplitude, and phase.
a sine wave (~)
The voltage and current are delivered in a sine wave that goes positive and then negative at 60 cycles per second. Google sine wave to see what a sine wave looks like.
A sine wave is, theoretically at least, the naturally-generated voltage produced by any rotating machine. This is because the voltage induced into a conductor that rotates within a magnetic field is proportional to the sine of the angle at which the conductor cuts the magnetic flux. In practise, a perfect sine wave is not produced in most practical machines, but it is close enough for practical purposes.
To calculate the peak voltage of an RMS voltage in a sine wave simply multiply the RMS voltage with the square root of 2 (aprox. 1,414) like this: 240 x 1,414 = 339,4 V RMS x sqr.root of 2 = peak voltage
4volts x 2.8 =9.6 v
if that 144 is the peak voltage if its a sine wave the rms voltage is that voltage divided by sqrt(2) if not a sine wave (modified) you must find the area under the curve by integrating a cycle of that wave shape (root mean squared)
a sine wave (~)
The voltage of a transformer should be a sine wave but if the transformer is overloaded with excess voltage there could be nonlinear effects in the magnetic core that cause harmonics (i.e. departure from a sine wave) in the voltage. The current is determined by the load. If the load is resistive the current and voltage have the same waveform (by Ohm's law) but if the load is nonlinear, a diode rectifier for example, the current will depart from being a sine wave.
The voltage and current are delivered in a sine wave that goes positive and then negative at 60 cycles per second. Google sine wave to see what a sine wave looks like.
If a square wave is used instead of a sine wave in a transformer, the output power will operate at a different frequency. This will produces varying levels of voltage and amperage based on the wave.
A sine wave is, theoretically at least, the naturally-generated voltage produced by any rotating machine. This is because the voltage induced into a conductor that rotates within a magnetic field is proportional to the sine of the angle at which the conductor cuts the magnetic flux. In practise, a perfect sine wave is not produced in most practical machines, but it is close enough for practical purposes.
To calculate the peak voltage of an RMS voltage in a sine wave simply multiply the RMS voltage with the square root of 2 (aprox. 1,414) like this: 240 x 1,414 = 339,4 V RMS x sqr.root of 2 = peak voltage
the answer is 5.6vp-p
Assuming sine wave (it is different if not): Vp-p = 2.828 * Vrms
12.68V 3o * sin25 = 12.67854785
See the link belowA sine wave is computed by a mathematical function. A pure sine wave in a physical sense would exactly match the calculated value in the function at every point in time.
clamper