The volume of a cylinder is the area of its base multiplied by the height. [In this case, the "height" of the cylinder is the depth of the pool.]
The base of the pool is a circle with radius of 9 m. The area of a circle is the radius squared times pi, which in this case is 81*pi m^2. Multiply this by the depth of 3.5 and you get 283.5 * pi cubic meters.
The shape of the well will be cylindrical. Depth (h1) of well = 14 m Radius (r1) of the circular end of well = Width of embankment = 4 m From the figure, it can be observed that our embankment will be in a cylindrical shape having outer radius (r2) as and inner radius (r1) as. Let the height of embankment be h2. Volume of soil dug from well = Volume of earth used to form embankment Therefore, the height of the embankment will be 1.125 m.
The volume of a cylinder is V=PI*r2*h The radius of the cylinder is 3 cm and the height would be 1cm So V = PI*(3cm)2*(1cm) V is approx. 28.3 cm3
Assuming the radius is an inside dimension: The inner surface area of the cylinder is Pi x R² = 3.1416 x (3 x 3) = 3.1416 x 9 = 28.2744 sq cm. The area is multiplied by the depth of the sand to find its volume. 28.2744 sq cm x 1 cm = 28.2744 cu cm.
This is a clever problem. It sounds really complicated, but that's only becauseit's actually two simple problems rolled into one.The two problems are:1). Volume of a rectangular prism2). Volume of a cylinderBefore we get started, let's make sure you remember the formulas for both ofthose volumes:1). Rectangular prism . . . V = (length) x (width) x (height)2). Cylinder . . . Volume = (pi) x (radius)2 x (height)The attack is:-- Figure out the volume of the water that rained onto the roof.-- Realize that the same volume poured into the cylindrical tub.-- Figure out how deep that much water fills the cylinder.At this point, the hard part is done! The problem is as good as solved.-- 1.2 cm of rain falls on the 10m x 5.5m rectangular roof. How much water is sitting on the roof ?Volume = L x W x H = (10m) x (5.5m) x (0.012 m) = 0.66 cubic meter of water-- Now pour that water into the cylinder with 3m diameter. How deep is it ?Volume = (pi) x (radius)2 x (height) .We need to find the height, so solve this formula for the height.Divide each side of equation by (pi) x (radius)2 :Height = Volume / (pi) x (radius)2The volume is the 0.66 m3 that poured off of the roof.The radius is 1/2 of the diameter = 1.5m .So Height = (0.66)/(pi) x (1.5)2 = 0.09337 meter = 9.337 cm.
2*15*10 = 300 cubic cm
890.19m3
Volume = pi * radius^2 * height
The volume of the cylinder is found by multiplying the depth by the square of the radius and by 3.142. The radius of the beaker is thus 6.31 cubic meters.
Radius: 157/2*pi = 25 feet rounded to nearest integer Volume: pi*252*15 = 9375*pi cubic feet
1728 ft cubed
In order to work out the volume we must work out the radius: 2*pi*radius = 60 (the circumference) Divide both sides by 2*pi to find the radius: radius = 9.549296586 feet Volume = pi*radius2*height = pi*9.5492965862*16 Volume = 4583.662362 or 4584 cubic feet
This is a volume of 3.33 cubic meters.
The hole forms a cylinder with radius = 3/2 = 1.5 meters Hence volume = pi x 1.5 x 1.5 x 9 = 3.1415 x 2.25 x 9 = 63.61 cubic feet
A 28 meter square is 28 times 28 meters or 784 square meters. If it is one tenth of a meter (10 cm) deep, it has a volume of 78.4 cubic metersIf you mean 28 square meters (like a pool 4 meters by 7 meters) then the volume one tenth of a meter deep is 2.8 cubic meters.
Assuming the hole is a regular cylinder, the formula for volume is:V = pi * R * R * D. Where R = Radius and D = Depth or height.V = 2.14159 * 2.5 * 2.5 * 4 (2.14159 is approximately = pi)V = 2.14159 * 2.5 * 2.5 * 4 = 53.53975 cubic meters
None. A hole is the absence of the material.
10 x 20 x 1