15 inches (solved with the help of Pythagoras' theorem)
15 cm for the diagonal.
Using Pythagoras' theorem it is 26 inches in length
The diagonal is 3.231 meters.
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm
Area of a rectangle = length * width = 92 m * 18 m = 1656 m2
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
15 cm for the diagonal.
Using Pythagoras' theorem it is 26 inches in length
Approximately 15.62 feet.
The diagonal would be 12.53 meters.
To find the length of the diagonal in a rectangle, use the formula for calculating the hypotenuse of a right triangle: a² = b² + c². a² = 3² + 10² a² = 9 + 100 a² = 109 a = 10.44 m
The diagonal is 3.231 meters.
D2 = (57)2 + (24.5)2 = (3,249) + (600.25) = 3,849.25D = sqrt(3,849.25) = 62.0423 (rounded)
D2 = (57)2 + (24.5)2 = (3,249) + (600.25) = 3,849.25D = sqrt(3,849.25) = 62.0423 (rounded)
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
120 feet
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm