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What else can I help you with?
Is a parallelogram inscribed in a circle always a rectangle?
Yes. The corners must be right angles for it to be inscribed on the circle.
True or false if a parallelogram inscribed in a circle it must be a rectangle?
True.
Which of the following must be an equiangular polygon?
hexagon
How do you work out angles in a semi-circle?
An inscribed angle is an angle formed by two chords in a circle which have a common endpoint. This common endpoint forms the vertex of the inscribed angle.The other two endpoints define an intercepted arc on the circle Any angle inscribed in a semi-circle is a right angle. The proof is simply that the intercepted arc is 180 so the angle must be half of that or 90 degrees.
Assume that two chords in a given circle are the same distance from the center of the circle Which of the following must also be true?
They must be congruent.
If a parallelogram is inscribed in a circle then it must be a?
If a parallelogram is inscribed in a circle then it must be a cyclic quadrilateral.
Is a parallelogram inscribed in a circle always a rectangle?
Yes. The corners must be right angles for it to be inscribed on the circle.
True or false if a parallelogram inscribed in a circle it must be a rectangle?
True.
Which of the following must be an equiangular polygon?
hexagon
Is it true an acute angle inscribed in a circle must intercept a minor arc?
No, because there is no acute angle in a circle.
Does a triangle need to be completely in the circle to be inscribed?
yes ...all the angles of the triangle must touch a spot on the circle..
How many different inscribed circles can be inscribed in a given triangle?
There is only one possible circle that can be inscribed in any triangle because all of the sides of the triangle must touch the circle at some point. Also, there is only one "incenter" of each circle. The incenter is the center of an inscribed circle.
How do you work out angles in a semi-circle?
An inscribed angle is an angle formed by two chords in a circle which have a common endpoint. This common endpoint forms the vertex of the inscribed angle.The other two endpoints define an intercepted arc on the circle Any angle inscribed in a semi-circle is a right angle. The proof is simply that the intercepted arc is 180 so the angle must be half of that or 90 degrees.
Assume that two chords in a given circle are the same distance from the center of the circle Which of the following must also be true?
They must be congruent.
In order to circumscribe a circle about a triangle the circle's center must be placed at the incenter of the triangle.?
This statement is incorrect. To circumscribe a circle around a triangle, the circle's center must be located at the circumcenter, not the incenter. The circumcenter is the point where the perpendicular bisectors of the triangle's sides intersect, while the incenter is the point where the angle bisectors meet and is the center of the triangle's inscribed circle.
Does hexagon have obtuse angle?
Yes. A hexagon must have an obtuse angle.
How do you create a hexagon that when you move the points the angles don't change on GSP?
I'm not familiar with GSP, but if you move any vertex of a hexagon then it is no longer a hexagon. In order to maintain the shape (that is, the aspect ratio) you must move all vertices at the same time, relative to the centre of the hexagon. The easiest way to calculate where each vertex should be placed is to imagine the hexagon is circumscribed with a circle such that all the vertices touch the circle. Thus the centre of the circle is also the centre of the hexagon. So when you move any vertex, you are essentially increasing or decreasing the radius of the circle and/or rotating the circle around its centre. However, the centre never moves so you only need to know the horizontal and vertical distance of the vertex you moved relative to the centre of the circle, and Pythagoras' Theorem tells you the radius of the circle (X2 + Y2 = Z2), and thus you can determine the angle of the hypotenuse relative to the horizontal or vertical plane. Knowing the position of one vertex means you can work out all 6 vertices (hint: they are 60 degrees apart).
