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To find the coordinates of point D in parallelogram ABCD, we can use the property that the diagonals bisect each other. The midpoint M of diagonal AC can be calculated as M = (\left(\frac{0 + 10}{2}, \frac{0 + 4}{2}\right) = (5, 2)). Since point B is at (2, 4), we can find D by ensuring point M is also the midpoint of diagonal BD. Thus, we set up the equation: ((\frac{2 + x_D}{2}, \frac{4 + y_D}{2}) = (5, 2)). Solving gives us (x_D = 8) and (y_D = 0), so the coordinates of D are (8, 0).

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3w ago

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