To find the coordinates of point D in parallelogram ABCD, we can use the property that the diagonals bisect each other. The midpoint M of diagonal AC can be calculated as M = (\left(\frac{0 + 10}{2}, \frac{0 + 4}{2}\right) = (5, 2)). Since point B is at (2, 4), we can find D by ensuring point M is also the midpoint of diagonal BD. Thus, we set up the equation: ((\frac{2 + x_D}{2}, \frac{4 + y_D}{2}) = (5, 2)). Solving gives us (x_D = 8) and (y_D = 0), so the coordinates of D are (8, 0).
All parallelograms have 4 vertices.
4 sides and 4 vertices
Four.
4.
Oh, dude, a parallelogram has four vertices. Yeah, it's like a fancy way of saying it has four corners. So, if you ever need to count 'em, just look for those four points where the sides meet. Easy peasy!
A parallelogram has 4 vertices
All parallelograms have 4 vertices.
A parallelogram has four vertices- it's a quadrilateral.
4 sides and 4 vertices
Four.
4.
Yes and it has 4 of them.
It appears to be (8, 0) when plotted out on the Cartesian plane
To determine if a parallelogram on a coordinate grid is a rhombus, check if all four sides are of equal length. You can calculate the distance between each pair of adjacent vertices using the distance formula. Additionally, since the diagonals of a rhombus bisect each other at right angles, you can verify that the slopes of the diagonals are negative reciprocals of each other. If both conditions are met, the parallelogram is a rhombus.
Oh, dude, a parallelogram has four vertices. Yeah, it's like a fancy way of saying it has four corners. So, if you ever need to count 'em, just look for those four points where the sides meet. Easy peasy!
It is a flat faced 4 sided quadrilateral that has 4 vertices.
Not sure about a parallelgram, but a parallelogram has 4.