The area is 1.2 (1.16463) m2
27.713 square inches.
Given this area, the sides measure 52.92734 cm
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=Area of a equilateral triangle="root over of 3" /4 * "a square"Now I use this formula,where "a" is 10. So the answers come=43.3,which is 44.So the Correct answer is=44 inches.* * * * *Mostly correct, but:43.3 should be rounded to 43, not 44.The units for the area should be square inches, not inches.
Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.
There is only one basic shape for an equilateral triangle. The area can only vary as the length of the sides vary.
If the sides are different lengths it ain't equilateral...
In our example, the area of the equilateral triangle is 1/6 of the area of the regular hexagon
225(radical "3")/4
It will be 9 times as large. And that will be true for any plane shape, not just an equilateral triangle.
By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!
27.713 square inches.
The area is: 15.6 (15.58846) square inches.
60 because there are 3 sides in a triangle and 60 x 3 =180, triangles are always equal to 180 * * * * * The above "answer" has nothing to do with the question! The area of an equilateral triangle with sides of s cm is s*sqrt(3)/4 square cm.
Area of Equilateral Triangle A= S2 * (Root 3)/4, where A= Area of the triangle S= Side of the triangle.
Given this area, the sides measure 52.92734 cm
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.