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538J
heat will flow from the iron to the water until both are the same temperature
Temperature isn't governed by weight so both can have the same temperature. Do you mean which has a higher melting point? That's iron as silver melts at a lower temperature.
1 cubic foot of iron, at room temperature would weigh approx 2190 newtons.
The density of iron (at room temperature) is approx 7.87 grams/cm3. Therefore, volume of 63.6 grams = 8.08 cm3
38 cal
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required to raise the temperature of 2 kg of iron by 3 degrees Celsius, you can use the formula: Energy = mass x specific heat capacity x temperature change. Plug in the values to find the answer.
The amount of energy required to raise the temperature of a substance can be calculated using the formula: energy = mass x specific heat capacity x temperature change. For iron, the specific heat capacity is 0.449 J/g°C. Assuming the temperature change is 1°C, the energy required would be 3 kg x 1000 g/kg x 0.449 J/g°C = 1347 J.
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required, you can use the formula: Energy = mass x specific heat capacity x change in temperature. Plugging in the values, Energy = 5g x 0.45 J/g°C x (30°C - (-10°C)). This calculation would give you the energy in joules required to raise the temperature of 5 grams of iron from -10ºC to 30ºC.
0.11cal/g degrees C
compound of iron
To find the mass of the iron sample, you need to know the specific heat capacity of iron. Given that the heat energy required to raise the temperature is 562 Joules, you can use the formula: heat energy = mass x specific heat capacity x temperature change. With the specific heat capacity of iron (0.45 J/g°C), you can calculate the mass of the iron sample.
The specific heat capacity of iron is 0.45 J/g°C. Therefore, the energy required to raise the temperature of 3 kg (3000 g) of iron by 3°C is calculated as follows: Energy = mass x specific heat capacity x temperature change. Plugging in the values, we get Energy = 3000g x 0.45 J/g°C x 3°C = 4050 Joules.
1935 J
538J
Iron melts at a temperature of around 2,800 degrees Fahrenheit (1,538 degrees Celsius). This high temperature is required to break the strong metallic bonds that hold the iron atoms together in a solid state, allowing them to move freely as a liquid.
The specific heat capacity of iron is 0.45 J/g°C. To find the energy required to raise the temperature of 2kg of iron from 20°C to 23°C, you would use the formula: Energy = mass x specific heat capacity x change in temperature. So, Energy = 2,000g x 0.45 J/g°C x (23°C - 20°C). Calculate this to find the energy required.