How many nickels and dimes are there if 344 coins total 28.75?

Answer 1

Assuming all the coins are either nickels or dimes: Let's call the number of nickels n and the number of dimes d.

Since there are 344 coins, we can write the equation:

n + d = 344There are 2,875 cents (28 dollars is 2,800 cents plus the 75 cents left over). Since nickles are five cents and dimes are 10 cents, we can write the equation:

5n + 10d = 2,875We now have two equations:

n + d = 344

5n + 10d = 2,875These equations can be solved by substation or elimination. Here we'll solve them by elimination. We'll multiply the top equation by 10:

10n + 10d = 3,440

5n + 10d = 2,875Now subtract the bottom equation from the top one, which gives:

5n = 565Divide both sides by 5:

n = 113So there are 113 nickles. Plug that back into the equation n + d = 344 to find the number of dimes:

113 + d = 344

d = 231So there are 113 nickels and 231 dimes.