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dime = 0.10

nickle = 0.05

(1) 0.10d + 0.05n = 6.05

(2) 2x 0.10d + 0.05(n-10)=9.85

0.20d + 0.05n - 0.5 = 9.85

0.20d + 0.05n = 10.35

To make things easy, I'll multiply everything by 100

(1) 10d + 5n = 605

(2) 20d + 5n = 1035

(1) 5n = 605 - 10d

n = 121 - 2d

(2) 5n = 1035 - 20d

n = 207 - 4d

121 - 2d = 207 - 4d

121 + 2d = 207

2d = 86

d = 43

43 Dimes

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Q: Joe has a collection of nickels and dimes that is worth 6.05 If the number of dimes was doubled and the number of nickels was decreased by 10 the value of the coins would be 9.85 How many dimes?
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