The largest possible values for the integers are 47, 49, and 51.
If possible, find the largest and smallest possible values of the variable under study. Then the range = Largest Value minus Smallest Value.
None. Integers can be negative, absolute values cannot. Absiolute values can be rational or irrational fractions, integers cannot.
Find the two numbers with the largest magnitudes (absolute values). The sum of their squares will be the maximum.
Let the three consecutive integers be a, b, & c. Square of c is 25 more than a*b:c2 = 25 + a*b; also the integers are consecutive, so a+1 = b & b+1 = cput a & b in terms of c, so b = c-1 & a = b-1 = c-2, substitute these into original equation:c2 = 25 + (c-2)*(c-1) = 25 + c2 - 3*c +2 --> c2 = 27 + c2 - 3*c --> 0 = 27 - 3*cc = 9 and from the 'consecutive' equations: b = 8& a = 7Substitute these values back into the original equation to make sure it works.92 = 81 and 8*7 = 56. 81 is 25 more than 56.
There are infinitely many possible solutions. Even if you limit your answer to integers, there are over a hundred. One possible answer {16, 26, 28, 30, 34, 34}
A discontinuous variable is a variable that has distinct categories. Blood type is a good example. You could be A, B, AB or O. This contrasts with a continuous variable such as height or weight, where there are an almost infinite number of possible values. Data for discontinuous variables is usually represented using a bar graph or pie chart, but never a scatter graph.
If possible, find the largest and smallest possible values of the variable under study. Then the range = Largest Value minus Smallest Value.
None. Integers can be negative, absolute values cannot. Absiolute values can be rational or irrational fractions, integers cannot.
Find the two numbers with the largest magnitudes (absolute values). The sum of their squares will be the maximum.
1. A single bit can represent two different values, 0 and 1. Then simply take the largest of those two possible values, 1, and that's your answer.
Let the three consecutive integers be a, b, & c. Square of c is 25 more than a*b:c2 = 25 + a*b; also the integers are consecutive, so a+1 = b & b+1 = cput a & b in terms of c, so b = c-1 & a = b-1 = c-2, substitute these into original equation:c2 = 25 + (c-2)*(c-1) = 25 + c2 - 3*c +2 --> c2 = 27 + c2 - 3*c --> 0 = 27 - 3*cc = 9 and from the 'consecutive' equations: b = 8& a = 7Substitute these values back into the original equation to make sure it works.92 = 81 and 8*7 = 56. 81 is 25 more than 56.
There are infinitely many possible solutions. Even if you limit your answer to integers, there are over a hundred. One possible answer {16, 26, 28, 30, 34, 34}
The integers are 43 and 44. The answer can be found by representing the two consecutive numbers as "n" and "n+1". n2 + (n+1)2 = 3785 n2 + (n2 + 2n + 1) = 3785 2n2 + 2n + 1 = 3785 2n2 + 2n - 3784 = 0 n2 + n - 1892 = 0 (n + 44) (n-43) = 0 n = -44, +43 The answer is restricted to positive values, so n = 43 and n+1 = 44
There can be no numbers of any kind that lie between the number 24. The word "between" implies two values which are different so that there is some "between" to be found.
d integers
The set of positive integers is {1, 2, 3, 4, 5, ...}. Because the values approach positive infinity there is no largest positive integer. If you pick any positive integer, you can always create a larger one by simply adding 1 to it. So there can be no largest positive integer.
For each pair of such integers, find the difference between the absolute values of the two integers and allocate the sign of the bigger number to it.