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Q: What is the next number in this sequence 1 8 27 64?

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The sequence represents the cube of integers starting at 1 and increasing by 1 at each step. 13 = 1 : 23 = 8 : 33 = 27 : 43 = 64 : then next two numbers are 53 = 125 : 63 = 216

-3 x cube numbers 1, 8, 27, 64, etc.

The missing number in this sequence is 64, or 4 raised to the third power. You find the answer by noting that each number in the sequence is a counting number starting at 1 that is raised to the third power. For example, 2 raised to the third power (2 x 2 x 2) is 8.

These are square numbers of 3, 4, 5 with alternating sign, I'd expect to continue the sequence with 36, -49, 64, -81, 100

They are 1/2 the previous term and so the next term will be -32

Related questions

125 (the sequence is successive numbers cubed)

343.

64. It's the sequence f(n) = n^3

13 ...23 ...33 ...43 ...53=125■

The next one is 125.

Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.

The next number in the sequence 2, 4, 16, 64 is 256.

1 8 27 64 125 216 343

64

It looks like 64 is the most likely answer.. There might be other patterns that I don't see. 13 23 33 43 1 8 27 64

The next number in the sequence is... 64

121

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