Q: When you divide the number by 7 the remainder is 1. When you divide the number by 9 the remainder is 7. When you divide the number by 11 the remainder is 10?

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If you take any four consecutive numbers and divide them by 3, the remainders are as follows: 9/3 = 3 10/3 = 3 remainder 1 11/3 = 3 remainder 2 12/3 = 4 Therefore, the highest remainder you can have by dividing a whole number is 2.

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You repetitively divide the number by two, taking the remainder as the digit (in binary). When you divide by 2, the remainder will either be 0 or 1.Example: convert 23 (base 10) to binary:23/2 = 11, remainder 1 (this is the ones digit)11/2 = 5, remainder 1 (this is the twos digit)5/2 = 2, remainder 1, (this is the fours digit)2/1 = 1, remainder 0, (this is the eights digit)1/2 = 0, remainder 1, (this is the sixteens digit). So now combine the digits (sixteens is the highest digit in this number):23 (base 10) = 10111 (base 2)

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Related questions

9000000

Eleven.

If you take any four consecutive numbers and divide them by 3, the remainders are as follows: 9/3 = 3 10/3 = 3 remainder 1 11/3 = 3 remainder 2 12/3 = 4 Therefore, the highest remainder you can have by dividing a whole number is 2.

Yes- A remainder can be any number less than the dividend (the number by which the divisor is divided). An example of a 2 digit number is: 131/11=11 remainder 10.

You use multiplication. Example: Problem is- 11 divided by 2. You would take the 2 and times it by 5, (2x5=10) with a remainder of 1 to equal 11. The answer is 5 with a remainder of 1. Mathematics is a great subject, there are so many ways of calculating and deriving answers and generate the same answer. Here's another way of doing it, 11 divided by 2 11 is not divisible by 2 but 10 is , there are 5 2's in 10 and that remains 1 as your remainder therefore, 11 / 2 = 5 remainder 1 tip: if you are dividing a number , look for the nearest multiple of the number and then the remaining is your remainder. You can have an answer as well with a decimal and that would be another lesson. hope this helps

If your improper fraction does not produce a remainder when you divide it, then it's just a whole number. 22/11 = 2

Yes, you can have a remainder of 5 when you divide by 6. If you divide 11 by 6, it will go into it one time with a remainder of 5.

Because 22 is the smallest number that both 2 and 11 divide into evenly with no remainder.

Because 33 is the smallest number that both 3 and 11 divide into evenly with no remainder.

Divide the numerator by the denominator, using integer division. The result is the integer; put the remainder over the denominator. Thus, 11/10 = 1 1/10.

The largest [integer] remainder is 10. If the remainder was any more you would get one (or more) lots of 11.

85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11