Divide the number by thirteen. If the answer comes out even with no remainder, the number is divisible by thirteen.
It's not. The quotient isn't a whole number.
Add up all the numbers in the number and see if it's divisible by three
12 will divide into it evenly with no remainder.
If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7. Example: 686 68 - 12 = 56 56 is divisible by 7. 686 is divisible by 7.
973 is divisible by: 1, 7, 139, 973.
No, it is not.
Double the last digit, subtract it from the rest. If the result is divisible by 7, the whole number is divisible by 7.
If you double the last digit and subtract it from the rest of the number and the answer is zero or divisible by 7, then the whole number is divisible by 7.
No, it is not divisible by 1234 nor by 6.
No.
think of "reverse operations"...1234 times 6 would equal a # that is divisible by 1234 and 6, due to that multiplication is the reverse operation of division. or 7404
6,170
Yes. 1,234 ÷ 2 = 617
just dividing it
There are 100 integers between 1,234 and 2,345 that are divisible by 11.
Yes, it is divisible by two. 1234 divided by two is 617. To determine if it is an even number look at the last digit in the number (in this case it is 4) and if it's divisible by 2 it's even.
1234
181093
1234
Yes, 2131 is not divisible by 3. The sum of its digits (2+1+3+1=7) is not divisible by 3, so the number itself is not divisible by 3.