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The factors of 117 are 1,3,9,13,39,and 117The factors of 117 are 1, 3, 9, 13, 39, and 117.1,3,9,13,39,and 1171x117;3x39;9x13To find the factors of a number, it is helpful to know the rules for checking if something is a divisor. One rule is that if a numbers digits add up to 9, the number divides by 9. In this case, 117 has digits which add up to 9, and so can be divided by 9. If we do this, we get 13, which is prime. Thus the prime factors are 3, 3 and 13. These can be combined to get the other factors. Therefore the factors of 117 are 1, 3, 9, 13, 39 and 117.
The factors of 8 are 1, 2, 4, and 8. The factors that add up to 10 are 2 and 8.
It wasn't me, but I would have come up with 33. The four factors of 33 add up to 48.
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-32
8 and 5
-3 and 16.
-13
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Add them up. The factors of 9 are 1, 3 and 9. The sum of the factors is 13.
You are 9.
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The factors of 9 are 1, 3, and 9. 1 + 3 + 9 = 13
I believe you are thinking of a prime number. Ex. The factors of 2 are 1 and 2. The factors of 13 are 1 and 13.
Because all of its factors also known as 13 and 1 add up to be more than the number itself 13.
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