0
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (1 plus or minus the square root of 253) divided by 2
x = 8.452986860293432
x = -7.452986860293433
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∙ 8y ago
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∙ 9y agoFind two numbers whose sum is -2 and whose product is -3.
Equivalently, find two positive numbers such that their difference is 2 and their product is 3.
The numbers are 1 and 3.
Since the middle term is negative, the larger of these numbers is negative in its factor.
The factorisation is (x - 3)*(x + 1)
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∙ 8y ago(x + the square root of 3)(x - the square root of 3)
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∙ 12y agoThe expression does not have rational factors.
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∙ 8y ago(x + 1)(x - 3)
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∙ 11y ago(x - 1)(x2 + x + 1)
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∙ 13y agoFactor x2-3 is: (x+sqrt3)(x-sqrt3).
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