Divid 128 repeatedly by the smallest prime numbers you can find until you get to 1. Like this:
128 / 2
64 / 2
32 / 2
16 / 2
8 / 2
4 / 2
2 / 2
You can see from this that the only prime factor of 128 is 2
The only prime factor of 128 is 2 because 2 x 2 x 2 x 2 x 2 x 2 x 2 = 128
Their product.
2048/128 = number of chips.
1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024
The GCF of 158 and 256 is 2. This leaves 79 and 128 remainder after division respectively. There is actually no other common factor aside from 1 between them as 79 is prime and doesn't go into 128.
It is 2 and as a product of its prime numbers in exponents 2^7 = 128
2x2x2x2x2x2x2=128 27 = 128
As a product of its prime factors in exponents: 2^7 = 128
The only prime number (factor) of 128 is 2.
The only even prime number is 2.
It is a composite number.
Its prime factor is 2 and as a product of its prime factor 2 to the power of 7 = 128
27
128 is a composite number. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 are neither prime, nor composite.
Prime factorization is breaking down a number into all of the prime numbers that make it up.For example, in 128, since it is even, the easiest first step would be diving by two, a prime number.64 * 2 = 128. Now divide 64, another even number, by two.32 * 2 * 2 = 128. Divide 32 by two.16 * 2 * 2 * 2 = 128. Divide by two again.8 * 2 * 2 * 2 * 2 = 128. Divide by two again.4 * 2 * 2 * 2 * 2 * 2 = 128. Divide by two a final time.2 * 2 * 2 * 2 * 2 * 2 * 2 = 128. This is your prime factorization.But you write it condensed, so 27 would be the prime factorization for 128.
2^7
2 x 2 x 2 x 2 x 2 x 2 x 2