A sample of gas occupies 2.78 x 103 mL at 25oC and 760 mm Hg What volume will the gas sample occupy at the same temperature and 475 mm Hg?

Answer 1

18.0L

Answer 2

Using Boyle's Law, the initial volume is directly proportional to the pressure. By decreasing the pressure to 475 mm Hg, we can calculate the new volume by V2 = (P1/P2) * V1. Plugging in the values, V2 = (760/475) * 2.78 x 10^3 mL = 4.45 x 10^3 mL.

Answer 3

The volume that the gas sample will occupy at the same temperature and 475 mmHg is 4448 mL. In significant figures, the answer would be 4400 mL

To find this, you can use the Combined Gas Law, (P1V1)/T1=(P2V2)/T2. First, you need to convert your temperature from degrees Celsius to Kelvin. You can do this by adding 273 to 25, which gives you 298 K. Then you can plug in the given values for volume, pressure, and temperature.

The equation should look like this:

(760 mmHg * 2.78 x 103 ml) / 298 K = (475 mmHg * V2) / 298 K

Then you can solve for V2 to find the unknown volume.

Answer 4

1.27*10^3 mL

Answer 5

Pv/t = pv/t

Answer 6

2800 ml