How do you balance the chemical equation C2H5OH O2 CO2 H2O?

Answer 1

C4H10 + 13/2O2 ---> 4CO2 + 5H2O

(1) First balance the carbon atoms: There are 4 on the left, so you'll need 4 on the right. So put a 4 in front of CO2

(2) Next balance the hydrogen atoms: there are 10 on the left, so you'll need 10 on the right. Since you have a water molecule, put 5 in front of H2O (5*2 = 10).

(3) Finally balance the oxygen atoms: on the right you have 4*2 (from the carbon dioxide) + 5*1 (from the water) = 8+5 or 13. So you now need 13 atoms of oxygen on the left. So put 13/2 in front of O2 (13/2 * 2 = 13)

(4) Now get rid of the fraction in front of O2 by multiplying all the coefficients by 2, to get your final balanced equation:

2C4H10 + 13O2 ---> 8CO2 + 10H2O

Answer 2

Unbalanced: C2H4 + O2 → H2O + CO2

Balanced: C2H4 + 3O2 → 2H2O + 2CO2

Answer 3

2C2H6 + 7O2 -> 4CO2 + 6H2O

Always balance O2 last and pay attention to the hydrocarbon arrangement.

Answer 4

The chemical equation is:
C2H5OH + O2 = 2 CO2 + 3 H2O

Answer 5

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

Answer 6

C2h4o2 + 2 o2 = 2 co2 + 2 h2o