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How many gallons of water in of 8 inch pipe 70 feet long?
182.8 gallons of water.
How many gallons of water are in an area of 15 inch by 70 inch and a half?
4.578 gallons for every inch the water is deep.
How many gallons in 70 pints?
8.75 gallons is 70 pints---1 pints = .125 gallons
Percentage of the planet that is water-?
The percentage of the plant that is covered with water is 70 percent.
What is the solute of 70 percent alcohol and 30 percent water?
You can say that water is the solute.
Percent of water that makes up earth?
70% of water, 326,000,000,000,000,000,000 gallons.
How much is 70 percent out of 5 gallons?
70 percent out of 5 gallons = 3.5 gallons70% of 5 gallons= 70% * 5 gallons= 70%/100% * 5 gallons= 35/10 or 3.5 gallons
70 gallons of water equal how many pounds?
70 gallons of water equal about 584.5 pounds.
How many gallons of a 80 percent solution must mix with 70 gallons of 10 percent solution to get 70 percent solution?
420 gallons. Here's how to find it; If X = Gallons of 80% mix, 0.8*X + 0.1*70 = 0.7*(X+70) Which we can then solve, 0.8X + 7 = 0.7X + 49 0.1X = 42 X = 420
How many gallons of a 50 percent antifreeze solution must be mixed with 70 gallons of 30 percent antifreeze to get a mixture that is 40 percent antifreeze?
70gallons
How many gallons of water are there in 70 cubic feet?
523.64 US gallons
How many gallons is 70 cups of water?
8.75
How many gallons of 50 percent antifreeze solution must be mixed with 70 gallons of 10 percent antifreeze to get a mixture that is 40 percent antifreeze?
Let X = gallons of 50% antifreeze .5X + .1(70) = .4 (X + 70) .5X + 7 = .4X + 28 .1X = 21 X = 210 GALLONS
How many gallons of water in of 8 inch pipe 70 feet long?
182.8 gallons of water.
How many gallons of a 70 percent antifreeze solution must be mixed with 70 gallons of 25 percent antifreeze to get a mixture that is 60 percent antifreeze?
Suppose G gallons are required. At 70% concentration, this will contain 0.7*G gallons of antifreeze. The 70 gallons of 25% contains 17.5 gallons of the active ingredient. In total, then, there are (G + 70) gallons containing 0.7G + 17.5 gallons of antifreeze and this represents 60%. So (0.7G + 17.5) / (G + 70) = 60/100 10*(0.7G + 17.5) = 6*(G + 70) 7G + 175 = 6G + 420 G = 420 - 175 = 245. Answer: 245 gallons.
How many gallons of a 80 percent antifreeze solution must be mixed with 70 gallons of 20 percent antifreeze to get a mixture that is 70 percent antifreeze?
70 gallons of 20% solution contains 70*0.2 = 14 gallons of antifreeze. Suppose you need G gallons of the 80% antifreeze solution. This will contain 0.8*G gallons of antifreeze. Total volume of solution = G + 70 gallons Volume of antifreeze required in this solutions to make it a 70% solution is 0.7*(G + 70) = 0.7G + 49 gallons. Volume of antifreeze = 14 + 0.8G gallons So 0.7G + 49 = 14 + 0.8G 0.7G + 35 = 0.8G 35 = 0.1G 350 = G Answer: 350 gallons.
How many gallons of a 60 percent antifreeze solution must be mixed with 70 gallons of 30 percent antifreeze to get a mixture that is 50 percent antifreeze?
Suppose G gallons are required. G gallons @ 60% implies 0.60*G gallons of the active ingredient. 70 gallons @ 30% implies 70*0.3 = 21 gallons of the active ingredient. This makes a total of (G + 70) gallons containing (0.6G + 21) gallons of active ingredient. The mixture is (0.6G + 21)/(G + 70) which is to be 50% or 0.5 So 0.6G + 21 = 0.5G + 35 or 0.1G = 14 which gives G = 140 gallons
