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70% of a 55-gallon drum is 38.5 gallons.

70% of an 8-ounce tumbler is 0.04375 of a gallon.

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โˆ™ 2010-12-02 21:07:35
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How many gallons of water is 70 percent?
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Percent of water that makes up earth?

70% of water, 326,000,000,000,000,000,000 gallons.


How much is 70 percent out of 5 gallons?

70 percent out of 5 gallons = 3.5 gallons70% of 5 gallons= 70% * 5 gallons= 70%/100% * 5 gallons= 35/10 or 3.5 gallons


70 gallons of water equal how many pounds?

70 gallons of water equal about 584.5 pounds.


How many gallons of a 80 percent solution must mix with 70 gallons of 10 percent solution to get 70 percent solution?

420 gallons. Here's how to find it; If X = Gallons of 80% mix, 0.8*X + 0.1*70 = 0.7*(X+70) Which we can then solve, 0.8X + 7 = 0.7X + 49 0.1X = 42 X = 420


How many gallons of a 50 percent antifreeze solution must be mixed with 70 gallons of 30 percent antifreeze to get a mixture that is 40 percent antifreeze?

70gallons


How many gallons of water are there in 70 cubic feet?

523.64 US gallons


How many gallons is 70 cups of water?

8.75


How many gallons of 50 percent antifreeze solution must be mixed with 70 gallons of 10 percent antifreeze to get a mixture that is 40 percent antifreeze?

Let X = gallons of 50% antifreeze .5X + .1(70) = .4 (X + 70) .5X + 7 = .4X + 28 .1X = 21 X = 210 GALLONS


How many gallons of water in of 8 inch pipe 70 feet long?

182.8 gallons of water.


How many gallons of a 70 percent antifreeze solution must be mixed with 70 gallons of 25 percent antifreeze to get a mixture that is 60 percent antifreeze?

Suppose G gallons are required. At 70% concentration, this will contain 0.7*G gallons of antifreeze. The 70 gallons of 25% contains 17.5 gallons of the active ingredient. In total, then, there are (G + 70) gallons containing 0.7G + 17.5 gallons of antifreeze and this represents 60%. So (0.7G + 17.5) / (G + 70) = 60/100 10*(0.7G + 17.5) = 6*(G + 70) 7G + 175 = 6G + 420 G = 420 - 175 = 245. Answer: 245 gallons.


How many gallons of a 80 percent antifreeze solution must be mixed with 70 gallons of 20 percent antifreeze to get a mixture that is 70 percent antifreeze?

70 gallons of 20% solution contains 70*0.2 = 14 gallons of antifreeze. Suppose you need G gallons of the 80% antifreeze solution. This will contain 0.8*G gallons of antifreeze. Total volume of solution = G + 70 gallons Volume of antifreeze required in this solutions to make it a 70% solution is 0.7*(G + 70) = 0.7G + 49 gallons. Volume of antifreeze = 14 + 0.8G gallons So 0.7G + 49 = 14 + 0.8G 0.7G + 35 = 0.8G 35 = 0.1G 350 = G Answer: 350 gallons.


How many gallons of a 60 percent antifreeze solution must be mixed with 70 gallons of 30 percent antifreeze to get a mixture that is 50 percent antifreeze?

Suppose G gallons are required. G gallons @ 60% implies 0.60*G gallons of the active ingredient. 70 gallons @ 30% implies 70*0.3 = 21 gallons of the active ingredient. This makes a total of (G + 70) gallons containing (0.6G + 21) gallons of active ingredient. The mixture is (0.6G + 21)/(G + 70) which is to be 50% or 0.5 So 0.6G + 21 = 0.5G + 35 or 0.1G = 14 which gives G = 140 gallons

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