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Given the balanced equation

C10H8 + 12O2 --> 10CO2 + 4H2O

In order to find the mass in grams of CO2 that can be produced from 25.0 moles of C10H8, we must convert from moles to mass (mol --> mass conversion).

25.0 mol C10H8 * 10 molecules CO2 * 44.01g CO2 = 1.1025x104 (11025)g CO2

------------------------- 1 molecule C10H8

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11y ago
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Wiki User

9y ago

The combustion of butane is 2 C4H10 + 13 O2 = 8 CO2 + 10 H2O. Every two moles of C4H10 can produce 10 moles of water, so given 12.5 moles of butane, 62.5 moles of water are made.

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13y ago

Two, this is due to the oxygen being the limiting element to form water. If this compound was split to form water would leave C2H4 which is Ethene.

After burning with oxygen: six

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Wiki User

13y ago

If the reaction is complete combustion, all of the hydrogen in C3H8 will be converted to water, with formula H2O. Therefore, 4 moles of water will be produced.

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11y ago

15

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4y ago

26

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Q: How many moles of water can be produced from two moles of C2H6O?
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