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0.063 g of oxalic acid * (1 mol H2C204*2H2O / 126.07 g) = 0.0004997 mol H2C2O4*2H2O 0.0004997 mol H2C204 / 0.250 L = 0.001999 M of H2C2O4

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15y ago
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4mo ago

To calculate the molarity, you need to know the molar mass of oxalic acid dihydrate (C2H2O4•2H2O) which is approximately 126.07 g/mol. First, convert 25.5 mg to grams (0.0255 g), then calculate the number of moles using the molar mass. Next, divide the number of moles by the volume of solution in liters (1.00 ml = 0.001 L) to find the molarity which is 0.255 M.

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14y ago

molar mass H2C2O4 = 2*1 + 2*12 + 4*16 = 90.0 g/mol = 90.0 mg/mmol

25.5 mg in 1.0 ml = 25.5/90.0 mmol/ml = 0.283 mmol/ml = 0.283 mol/L = molarity oxalic acid

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11y ago

.0056 M

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Q: If 25.5mg of oxalic acid dihydrate are dissolved in 1.00 ml of solution what is the molarity of the resulting solution?
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