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Kinetic Energy - EK (J) = 1/2mv2

Where m = mass (kg)
v = velocity (ms-1)

Therefore a 6.8 kg block travelling at 6 ms-1 has kinetic energy equal to:

(6.8/2) x 62

= 3.4 x 36

=122.4 Joules

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15y ago
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6mo ago

The kinetic energy of the block can be calculated using the formula: KE = 0.5 * mass * velocity^2. Plugging in the values, KE = 0.5 * 6.8 kg * (6 m/s)^2 = 122.4 joules. So, the kinetic energy of the block is 122.4 joules.

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Q: What is the kinetic energy of a block if a 6.8 kilogram block is sliding down a horizontal frictionless surface at a constant speed of 6 meters per second?
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