4.0 (g/L) / 40 (g/mol NaOH) = 0.10 (mol/L NaOH) = 0.10 M
The molarity of that solution is 0.82, based on sodium phosphate's molar mass and the given volume of solution. Since there are three sodium ions for every one formula unit of sodium phosphate, the molar concentration of Na+ ions is 0.82(3)=2.46.
Molar heat of solution
This is a molar concentration.
The concentration of the solute is 0,5 molar.
PH11
Look up or calculate the molecular weight/molar mass of FeCl3. Then... 40.0 g FeCl3/MW FeCl3/0.275 L = M (concentration of FeCl3 in solution)
The molarity of that solution is 0.82, based on sodium phosphate's molar mass and the given volume of solution. Since there are three sodium ions for every one formula unit of sodium phosphate, the molar concentration of Na+ ions is 0.82(3)=2.46.
Molar heat of solution
This is a molar concentration.
to make a 2 molar solution of NaOH, what is necesary
0.01 Molar
1M solution has higher concentration than 1m solution
The concentration of the solute is 0,5 molar.
0.000001 molar
The molar concentration is 2.91 M of ammonia.
eight (8)
The formula of lead (II) nitrate is Pb(NO3)2. This shows that in any solution of lead nitrate only, the molar concentration of nitrate ions will be twice as much as the molar concentration of lead (II) nitrate. Molar concentration is defined as number of moles per liter of solution, and 800 mL is the same as 0.800 liters. Therefore the molar concentration of nitrate ions in the specified solution will be 2(0.027823/0.800) or 6.96 X 10-2 . Only three significant digits are justified because that is the number of digits in 800.