What is the percentage of oxygen to the nearest tenth in this compound NiSO4 x 7H2O?
a+ answer:62.90
The percentage is 44,15 % for NiSO4.7H2O.
The name of the compound NiSO4 x 7H2O is nickel(II) sulfate heptahydrate. It has a molecular weight of 280.86 grams per mole, and in appearance it is a crystalline substance.
Nickel(II) sulfate
55
ZnSO4 + N, it's a displacement reaction
Oxygen is a chemical element with the symbol O and atomic number of 8. Its percentage composition in the compound NiSO4 x 7H2O is 31.3%.
The relative molecular weight of the compound nickel (II) sulphate heptahydrate NiSO4 7H2O is 280. 86. The total mass of oxygen in the compound is 176 g. Therefore the total percentage of oxygen to the nearest tenth is 60 percent
44.9
This compound is call Nickel sulfate NiSO4
This compound is call Nickel sulfate NiSO4
NiSO4 * 7H2O NiSO4 * 7H2O
The percentage is 44,15 % for NiSO4.7H2O.
62.816
Nickel sulfate is an ionic compound.
This compound is nickel sulfate heptahydrate.
molecular weight of NiSO4.7H2O is 1101.3 and it has 11 oxygens. So percentage of oxygen = (7 x 16) / 1101.3 = 112 / 1101.3 = 0.102 or 10.2%
The compound NiSO4 7H2O is magnesium sulfate heptahydrate. It is a type of inorganic salt that is commonly known as Epsom salt.