Answer:
0.00900 has 3 significant figures, "9", "0", and "0". The significant figures are shown in bold. This is true because:
-All non-zero digits are significant (the nine)
-All zeroes trailing the first non-zero digits are NOT significant (the first three zeroes)
-If a number has a decimal point, all zeroes AFTER the last non-zero digit are significant (the last two zeroes). Therefore, it has 3 significant digits.
Chat with our AI personalities
Oh, dude, the significant digits in 0.0098 are 2. See, the zeros before the 9 don't count because they're just placeholders. So, you're left with the 9 and the 8, making it a grand total of 2 significant digits. Like, who knew math could be so chill, right?
Three
Significant Figures
à Non-zero numbers are always significant figures.
à Zeros are tricky:
- If zeros appear before a non-zero (called leading zeros), they are NEVER significant (ex: 0.025)
- If zeros fall between non-zero numbers, they are ALWAYS significant (ex: 205)
- If zeros come at the end of the number, they WILL be significant only IF there is a decimal present (ex: 250.0)
à Exact numbers (or counting numbers) have infinite significant figures. For example, if we count 3 pencils, we know there are exactly 3 pencils. Or, when we say 1 inch = 2.54 cm, we know this is for exactly 1 inch.
There are 3 significant digits in 4.00 and 2 significant digits in 7.0. Zeros between non-zero digits or at the end of a number after a decimal point are considered significant.
36.8 pentameters has three significant digits.
There are four significant digits in the number 6.741.
3 significant digits because first zeros are just placeholders
The term for eliminating digits that are not significant is called rounding or truncating. This process involves reducing the number of digits in a calculation to match the precision of the measurement.