A #3 copper conductor will limit the voltage drop to 3% or less when supplying 5 amps for 1500 feet on a 120 volt system.
The formula you are looking for is W = A x V.
I = W/E. Current is equal to Watts divided by Volts. 1500/120 = 13 amps. A #14 is rated at 15 amps. A conductor can only be loaded to 80% for a continuous load so 80% of 15 equals 12 amps. Too small for the 1500 watt load. A #12 conductor is rated at 20 amps times 80% equals 16 amps for a continuous load. To answer your question, no, a #16 conductor will not handle a 1500 watt load.
The circuit breaker is used to protect the conductor that is connected to it from an overload condition. On a motor load the breaker has to be sized 250% of the motors full load amperage. Some circuits can be only loaded to 80% capacity and this is governed by the sizing of the breaker. Without knowing what the load amperage is, this question can not be answered.
Yes, as long as it has the necessary ampacity for the load and is properly fastened at each terminal. For example, we have a 4/0 aluminum cable feeding our 200 A subpanel 120 feet away.
a 240 volt thermostat (or any 240 volt switch) is generally a 2-pole switch which means it breaks both wires going to the load You can use it for 120 volt loads by using one of the two poles for the "hotleg" wire and just splice through the neutral wire this is a 2-pole switch (the two blades move as one handle) line___.__ \___._ load line___.__ \___._ load The second pole goes unused and gives you a spare for the future
without knowing load, cannot say
It depends on the load and bullet weight, but usually somewhere between 1000 and 1500 FPS.
1500
The formula you are looking for is W = A x V.
1500 lbs. that includes driver anything in cab and load
1500
Take a Load Off Your Feet was created in 1970-01.
When my horse does not load i try bribing him with oats or complete feed.
1500
1500
yes
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