A 300 MCM copper conductor, with a voltage drop of 3%, is needed when supplying 50 amps for 600 feet on a 120 volt system.
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∙ 2011-10-20 17:48:21You need amps
12 AWG.
It depends on the voltage source. watts = voltage * voltage / resistance and amps = voltage / resistance example 1: To produce 600W from a 120V source, you need a resistor of size 120V*120V/600W = 24 Ohm. This would pull 120V/24 Ohm = 5 amps. example 2: To produce 600W from a 240V source, you need a resistor of size 240V*240V/600W = 96 Ohm. This would pull 240V/96 Ohm = 2.5 amps.
At what voltage? Until you tell me the voltage I can't give you an answer. To find out Amps you need to divide the Watts by the Volts. At 120V you have 0.4 amps. At 12V you have 4 amps.
To carry 100 amps you would need to use AWG-1.
You need amps
You need amps
12 AWG.
It depends on the voltage source. watts = voltage * voltage / resistance and amps = voltage / resistance example 1: To produce 600W from a 120V source, you need a resistor of size 120V*120V/600W = 24 Ohm. This would pull 120V/24 Ohm = 5 amps. example 2: To produce 600W from a 240V source, you need a resistor of size 240V*240V/600W = 96 Ohm. This would pull 240V/96 Ohm = 2.5 amps.
At what voltage? Until you tell me the voltage I can't give you an answer. To find out Amps you need to divide the Watts by the Volts. At 120V you have 0.4 amps. At 12V you have 4 amps.
To carry 100 amps you would need to use AWG-1.
10 guage
A #3 copper conductor will limit the voltage drop to 3% or less when supplying 5 amps for 1500 feet on a 120 volt system.
It depends upon the distance, but typically a short to medium run (0-50 feet) of 12 gauge can carry 20 amps safely. There are charts that list the gauge of wire and the length of runs that can carry amperages safely. For instance, a 12 gauge wire run 150 feet can only carry 15 amps safely instead of 20. The longer the run, you need to drop a gauge as a general rule.
Wire is sized by the amperage that it is allowed to legally carry. To answer this question the amperage that you need at the garage must be stated.
The burners will most likely be 240V. By keeping the range at 240 volts it will use less amps that at 120V. Say a range and oven is rated at 9000 watts. Watts = amps x volts. 9000/240V = 37.5 amps. 9000/120V = 75 amps. As you can see at 120 volts the amperage is double over 240 volts. You would need a 100 amp breaker and #4 wire to accomodate the range on 120 volts.
You will need a 40 amp breaker using AWG # 8 wire running it a distance of no more than 50 feet.