A pyramid is a generic term used to describe a polyhedron with a polygonal base and triangles rising from that base to meet at an apex. The polygonal base can have any number, n, of sides, provided that n>2. There is, therefore, no information about the number of lateral faces in the pyramid. Also, the surface area of a pyramid depends on its height and there is no information whatsoever about its height. It is, therefore, impossible to answer such an underspecified question.
The formula to find the area of an octagonal pyramid is area of base plus area of sides.
Calculate them and compare.
i have an answer for both a frustum of a pyramid and a frustum of a cone which do you need frustum of a cone just give both of them
To find the perpendicular height of a square pyramid, first compute for the volume of the pyramid. Then divide the volume by the area of the base to find pyramid's height.
160
105cm2
you dont
The formula to find the area of an octagonal pyramid is area of base plus area of sides.
A rhombus is a 4 sided quadrilateral whose sides are equal in lengths and can be measured with a ruler.
It has to do with the surface area formula: To find the total surface area of a pyramid, use this equation: Surface Area = B + 1/2 * P * s B = base area P = perimeter of the base s = slant height To find the volume of a Pyramid, substitute into this equation: V=1/3Bh B=base area h=height of pyramid
You can find the exact surface area for all of those shapes.
The surface area of a pyramid is the area of all the faces of the pyramid, for a pyramid with apex in the centre and a regular polygon as its base, (the bottom of a pyramid is the base, it is regular if all sides are the same length) the surface area is: B + 1/2(P * H) where B is the area of the base, P is the perimeter (area around) the base and H is the height of the pyramid.
Find the surface area of each of the four triangular faces (they need not be the same) and sum the individual areas.
The surface area of a pyramid is the area of all the faces of the pyramid, for a pyramid with apex in the centre and a regular polygon as its base, (the bottom of a pyramid is the base, it is regular if all sides are the same length) the surface area is: B + 1/2(P * H) where B is the area of the base, P is the perimeter (area around) the base and H is the height of the pyramid.
Surface area of any pyramid is 1/2Pl + B; where P=perimeter of the base, l=slant height and B= Area of the base.
If its a triangular based pyramid (tetrahedron) then it will have 4 equilateral triangle faces and so find the area of one face and multiply it by 4 to give the total surface area.
You add the lengths of all the sides. If the sides happen to be of equal length, you multiply this length by 7.