Best Answer

5872345098234783904672083946728390752430689723409687298290843 theres your answer

Q: Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.

Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.

Divide the sum of the three consecutive odd integers by 3: 45/3 = 15. The smallest of these integers will be two less than 15 and the largest will be two more than 15, so the three consecutive odd integers will be 13, 15, and 17.

Divide the sum of the three consecutive odd integers by 3: 93 / 3 = 31. The smallest of these integers will be two less than 31 and the largest will be two more than 31, so the three consecutive odd integers will be 29, 31, and 33.

Divide the sum of the three consecutive odd integers by 3: 159/3 = 53. The smallest of these integers will be two less than 53 and the largest will be two more than 53, so the three consecutive odd integers will be 51, 53, and 55.

Related questions

Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.

You've come to the right place. The integers are: 2, 4, and 6

Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.

Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.

Divide the sum of the three consecutive odd integers by 3: 45/3 = 15. The smallest of these integers will be two less than 15 and the largest will be two more than 15, so the three consecutive odd integers will be 13, 15, and 17.

Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.

The largest is 73.

Divide the sum of the three consecutive odd integers by 3: 93 / 3 = 31. The smallest of these integers will be two less than 31 and the largest will be two more than 31, so the three consecutive odd integers will be 29, 31, and 33.

Divide the sum of the three consecutive odd integers by 3: 225/3 = 75. The smallest of these integers will be two less than 75 and the largest will be two more than 75, so the three consecutive odd integers will be 73, 75, and 77.

x+(n+1)+3(n+2)= something then solve,

Divide the sum of the three consecutive odd integers by 3: 51 / 3 = 17. The smallest of these integers will be two less than 17 and the largest will be two more than 17, so the three consecutive odd integers will be 15, 17, and 19.