The smaller integer is 6, the larger integer is 32
The two integers are 6 and 7.
Let the smaller integer be x, then then larger integer is x + 2, and: 3x + (x + 2) = 58 → 4x = 56 → x = 14 → The two integers are 14 and 16.
a = b + 7; 2a = b2 - 1. Substituting: 2b + 14 = b2 - 1 or b2 - 2b - 15 = 0 Factors are (x - 5)(x + 3) b = 5, a = 12. Also works with b = -3 and a = 4
-1: Negative integers become smaller as their absolute value increases. Therefore, the first negative integer is the smallest. This answer assumes that -0 is excluded because 0 is neither positive nor negative.
Let x = 1st integer, since consecutive even integer differs by 2 then the 2nd integer = x + 2. So we have, x + 4(x + 2) = 48 x + 4x + 8 = 48 5x = 40 x = 8 (1st integer) Thus, the integers are 8 and 10. Check.
x > 16
The smaller integer is 17.
The two integers are 6 and 7.
The larger integer is 30. The smaller is 28.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
No.A positive integer is always larger than a negative integer. In the case of two negative integers, the integer with the larger absolute value is actually smaller.
no one wants to know the answer. its freaking math
A negative integer is a whole number that is smaller than zero. It is the additive inverse of a positive integer.
That's correct - there is none. For any integer, you can subtract one to get an even smaller integer.
With the number line in its normal orientations, the integer on the left is smaller.
6+7=13 and 6 and 7 are consecutive. 6 is the smaller integer so answer is 6
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