Q: There are quarters and dimes in a box Their total value is at most 4.50 Quarters are 5 times as many as dimes How many quarters and how many dimes are at most in the box?

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2.50 can be made up from 10 quarters or 25 dimes, for the first two ways. The smallest number of quarters that can be substituted for dimes without changing the sum is two, substituted for five dimes. Therefore, you can have: 20 dimes + 2 quarters, 15 dimes + 4 quarters, 10 dimes + 6 quarters, or 5 dimes + 8 quarters, four additional possibilities for a total of six..

The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?

The algebraic formula for this problem has the form 25x + 10(35-x) = 515 where x is the number of quarters (times 25 cents) and (35-x) is the number of dimes (times 10 cents) With the result that 25x + 350 - 10x = 515, yielding 15x = 165, and x = 11 So James has 11 quarters and 24 dimes, (2.75 and 2.40) equalling $ 5.15 total.

d = q + 3; 10d + 25q = 345. 10(q + 3) + 25q = 345 ie 35q = 315 so q = 9 and d = 12. Check: 9 quarters = $2.25, 12 dimes = $1.20, total $3.45.QED

$1.19 is the total.

Related questions

Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?

There are 39 combinations of dimes and quarters that will total 19.75 from 1 quarter and 195 dimes to 77 quarters and 5 dimes.

111 quarters, zero dimes, zero nickels 110 quarters, two dimes, one nickel 109 quarters, four dimes, two nickels

2.50 can be made up from 10 quarters or 25 dimes, for the first two ways. The smallest number of quarters that can be substituted for dimes without changing the sum is two, substituted for five dimes. Therefore, you can have: 20 dimes + 2 quarters, 15 dimes + 4 quarters, 10 dimes + 6 quarters, or 5 dimes + 8 quarters, four additional possibilities for a total of six..

The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?

If Keoki has 14 quarters and 8 dimes (for a total of 22 coins), she has $3.50 and $0.80 or $4.30 in coins. If Keoki has 15 quarters and 7 dimes (for a total of 22 coins), she has $3.75 and $0.70 or $4.45 in coins. If Keoki has 22 coins that are all dimes and quarters and their value in total is $4.35 as asked, there isn't a combination of coins that will permit her to have both 22 coins and $4.35 worth of coins.

4 quarters = $1.00 4 dimes = $0.40 4 nickels = $0.20 4 pennies = $0.04 Total: $1.64

12 quarters 6 dimes

Eighteen

The algebraic formula for this problem has the form 25x + 10(35-x) = 515 where x is the number of quarters (times 25 cents) and (35-x) is the number of dimes (times 10 cents) With the result that 25x + 350 - 10x = 515, yielding 15x = 165, and x = 11 So James has 11 quarters and 24 dimes, (2.75 and 2.40) equalling $ 5.15 total.

$2.70

3 quarters = 75Â¢ two dimes = 20Â¢ one nickel = 5Â¢ Total = 100Â¢ = $1.00